1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
neonofarm [45]
3 years ago
12

Rewrite the product as a power: (pls show work)

Mathematics
2 answers:
pshichka [43]3 years ago
7 0

Hello :3

I'm not sure if this is exactly what you're looking for but it would be

a to the power of 7

and y to the power of 7

Hope This Helps!

Cupkake~

miv72 [106K]3 years ago
6 0

(ay)^{7}

recalling the law of exponents

(ab)^{n} = a^{n} × b^{n}


You might be interested in
SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin
laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

<u>Empirical rule to determine the percent:</u>

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$Z(X)=\frac{x-\mu}{\sigma}

$Z(433)=\frac{433-\ 433}{90}=0

$Z(523)=\frac{523-\ 433}{90}=1

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. ((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%

Here μ to μ + σ = \frac{68\%}{2} =34\%

Hence 34% of the scores lie between 433 and 523.

8 0
3 years ago
Evaluate<br> 13- (-9)<br><br> need helpp
Viktor [21]

Answer:

The answer is 22.

Explanation:

Multiply -1 by -9.

13 + 9

Add 13 + 9.

22

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>22</u>.

6 0
2 years ago
The large rectangle shown here is 3cm by 5 cm. What is a direct way to determine the area of the rectangle in square centimeters
dlinn [17]

Answer:

Place the squares on the rectangle.

Step-by-step explanation:

Hello!

The area of the 1cm by 1cm square is 1 square cm.

We can solve for the area by placing multiple of those squares in the larger rectangle.

If we place it, we get 15 placed squares, with a total area of 15 square cm. This relies on the meaning of area, as we are simply measuring the number of square cm taken up by the object.

We would place 3 rows of 5 squares, representing a height of 3 cm (side length of 3 squares), and a length of 5 cm (side length go 4 squares).

This also proves the area formula A = L * W, as we multiple the side lengths to find the number of square units.

8 0
2 years ago
Which angle is supplementary to 65 degrees​
Alexeev081 [22]

Answer:

115°

Step-by-step explanation:

Supplementary angles equal 180.

180-65=115°

6 0
3 years ago
Read 2 more answers
Use the function below to find f(4). F(x) = 3x
Sonja [21]
Since F(X) = 3^X,

F(4) = 3^4 = 81
5 0
3 years ago
Read 2 more answers
Other questions:
  • each of the 13 dogs in the kennel got either a chew toy or a rubber ball if three more dogs got a chew toy than a rubber ball ho
    12·1 answer
  • 2x6+8-1 can anyone help?
    8·2 answers
  • Thanks guys for all the help :)
    10·1 answer
  • Which type of triangle will always have a perpendicular bisector that is also an angle bisector?
    11·1 answer
  • One winter day the temperature increased from a low of -5 f to a high of 40 f how many degrees did the temperature change
    8·1 answer
  • Pls help me
    8·1 answer
  • I'm in need of some desperate help ​
    6·1 answer
  • What is 0.1x30 I need help for this problem in math
    15·2 answers
  • Can you answer this question, please? It would help me so much
    7·1 answer
  • Is (5,50) a solution to the linear system y = 5x + 25 and y = 3x + 35? Explain your reasoning.
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!