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4 years ago

Can someone help me get better in math?

Mathematics

1 answer:

ddd [48]4 years ago

8 0

Answer:

I can, I'll follow you and so I will get a notification every time you ask a question. Then I will answer it.

Step-by-step explanation:

You might be interested in

Triangle ABC is congruent to triangle DFE. Find x.

Archy [21]

ΔABC ≡ ΔDFE

⇒ line EF = BC

Solve x:

3x - 4 = 20

3x = 24

x = 8

Answer: x = 8

4 0

3 years ago

I’ll give you brainliest for the first person with an answer

raketka [301]

Answer:

1296mm^2

Step-by-step explanation:

Surface Area of the Rectangular Prism to the left on top of the box:

Area of square = lw, 9mm * 9mm = 81mm, then multiply by 2 because 2 of the squares are a part of the surface, giving 162mm^2

Area of a rectangle =lw, 9mm * 9mm = 81mm, then multiply by 2 again, because 2 rectangles are a part of the surface, giving 162mm^2

So, the total surface area of the rectangular prism to the left on top, is 324mm^2

Surface Area of the Triangular Prism:

Area of a triangle: 1/2bh, and our base length would be 12, because we have to subtract 9 from 21 since the base length of the triangle isn't stated. Anyways, A = 1/2bh, so A = 1/2(12)(9) = 54mm^2, but multiply by two, so we get 108mm^2.

Area of the rectangle: lw, so 15mm * 9mm = 135mm^2

So, the total surface area of the triangular prism is 243mm^2

Surface Area of the Rectangular Prism at the bottom:

Area of the long rectangles in front = lw, 21mm * 9mm = 189mm^2, multiply by 2, 378mm^2

Area of the rectangles to the side = lw, 9mm * 9mm = 81mm^2, multiply by 2, 162mm^2

Area of the rectangle at the very bottom = lw, 21mm * 9mm = 189mm^2

So, the total surface area of the rectangular prism at the bottom is 729mm^2

Add all the total surface areas of each shape to get the total surface area of the figure:

324mm^2 + 243mm^2 + 729mm^2 = 1296mm^2

The surface area of the figure above is 1296mm^2

4 0

2 years ago

Solve using substitution. 7x-4y=-12 9x-4y=-20

MrRissso [65]

Answer:y= -4

Step-by-step explanation:

1 Solve for xx in 7x-4y=-127x−4y=−12.

x=\frac{4(y-3)}{7}

4(y−3)

2 Substitute x=\frac{4(y-3)}{7}x=

4(y−3)

into 9x-4y=-209x−4y=−20.

\frac{36(y-3)}{7}-4y=-20

36(y−3)

−4y=−20

3 Solve for yy in \frac{36(y-3)}{7}-4y=-20

36(y−3)

−4y=−20.

y=-4

y=−4

4 Substitute y=-4y=−4 into x=\frac{4(y-3)}{7}x=

4(y−3)

x=-4

x=−4

5 Therefore,

\begin{aligned}&x=-4\\&y=-4\end{aligned}

x=−4

y=−4

3 0

3 years ago

14 is a blank of 7 and 14

LiRa [457]

14 is a multiple of 7 and 14

6 0

3 years ago

How many times would you expect to role a 2 on a 6 sided die in 50 trials

Keith_Richards [23]

The six sided die has 6 sides (with numbers 1,2,3,4,5 and 6). That's why the probability to roll number 2 in one trial is equal to $\frac{1}{6}$ .If you'll dol 50 trials, then you can expect $\frac{50}{6}= \frac{25}{3}$ times to roll number 2 (8 or 9 times).

3 0

3 years ago