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1 answer:
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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Answer:
Center = (5,-3) and radius = 7
Step-by-step explanation:
(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.
(6) The given equation is :
The general equation of circle is given by :
...(1)
Where
(a,b) are the coordinates of the centre and r is the radius.
The given equation can be written as :
..(2)
Comparing equation (1) and (2) we get :
a = 5, b = -3 and r = 7
So,
Center = (5,-3) and radius = 7
Hence, this is the required solution.