Pls help if you actually can
1 answer:
The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
<h3>How to identify similar triangles?</h3>From the image attached, we see that we are given the Parallelogram GRPC. Thus;
A. The triangles that are similar would be ΔGCB and ΔPEB due to Angle, Angle, Angle similarity theorem.
B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;
∠CGB ≅ ∠PEB (Alternate Interior Angles)
∠BPE ≅ ∠BCG (Alternate Interior Angles)
∠GBC ≅ ∠EBP (Vertical Angles)
C. To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;
225/325 = PE/375
PE = 260 ft
BE/425 = 225/325
BE = 294 ft
Read more about Similar Triangles at; brainly.com/question/14285697
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Hello!
I've attached the diagram.
For this problem, since you have a right triangle, you can use the Pythagorean Theorem to fine the length of the ladder (the hypotenuse of the triangle).
Pythagorean Theorem (where c is the hypotenuse):
a² + b² = c²
The triangle's leg lengths are 8 and 6; substitute into the theorem:
8² + 6² = c²
Simplify:
64 + 36 = c²
100 = c²
10 = c
Answer:
The length of the ladder is 10 m.
I've attached the diagram.
For this problem, since you have a right triangle, you can use the Pythagorean Theorem to fine the length of the ladder (the hypotenuse of the triangle).
Pythagorean Theorem (where c is the hypotenuse):
a² + b² = c²
The triangle's leg lengths are 8 and 6; substitute into the theorem:
8² + 6² = c²
Simplify:
64 + 36 = c²
100 = c²
10 = c
Answer:
The length of the ladder is 10 m.
