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ale4655 [162]
2 years ago
10

Angie’s Bake Shop makes birthday chocolate chip cookies that cost $2 each. Angie expects that 10% of the cookies will crack and

be discarded. Angie wants a 60% markup on cost and produces 100 cookies. Assume that Angie can sell the cracked cookies for $1.10 each. What should Angie price each cookie?
Mathematics
2 answers:
wlad13 [49]2 years ago
8 0

Answer:

Step-by-step explanation:

the value of the cookies can be 1.20

Flura [38]2 years ago
7 0

Answer:

$ 3.43

Step-by-step explanation:

Given,

Total cookies = 100,

Cost price of each cookie = $ 2,

So, the total cost price = $ 200,

After marking up the price by 60%,

Total selling price = (100+60)% of 200

= 160% of 200

=\frac{160\times 200}{100}

= $ 320

Out of 100 cookies 10% are cracked or discarded,

Thus, the cracked cookies = 10% of 100

= \frac{10\times 100}{100}

= 10,

Then, the simple cookies = 100 - 10 = 90,

The price of each cracked cookie = $ 1.10

So, the selling price of cracked cookies = 1.10 × 10 = $ 11,

Now, let the price of each simple cookie = x dollars

So, the selling price of simple cookies = x × 90 = 90x dollars,

Thus, the total selling price = 90x + 11

⇒ 90x + 11 = 320

90x = 320 - 11

90x = 309

⇒ x = 3.43

Hence, the price of each cookie should be $ 3.43.

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Answer:

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Step-by-step explanation:

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Collect like terms

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Alex17521 [72]

Answer:

100/100

Step-by-step explanation:

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2 years ago
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ZanzabumX [31]
Hey there!

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8 0
3 years ago
Read 2 more answers
Suppose a baseball is thrown vertically upward from the ground with an initial velocity of Subscript[v, 0] ft/s. Its height abov
Zina [86]

Answer:

90.5

Step-by-step explanation:

Velocity is a time-derivative of displacement or the height, in this case.

s(t)=-16t^2+v_0t

v(t) = -32t+v_0

At maximum height, the velocity is 0 and the height is 128.

Substitute these values into both equations above,

0 = -32t+v_0

t=\dfrac{v_0}{32}

From the first equation,

128 = -16t^2 + v_0t

Substitute for t.

128 = -16(\dfrac{v_0}{32})^2 + v_0\times\dfrac{v_0}{32}

128 = -v_0^2/64 + v_0^2/32

128=\dfrac{v_0^2}{64}

v_0^2=8192

v_0=64\sqrt{2}=90.5

5 0
3 years ago
Do you know how to solve this with work to back it up?
ehidna [41]
Depends are you finding x or other variables
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