You solve an equation like this by adding the opposite of the constant to both sides of the equation.
... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b
... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0
... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V
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<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.
Answer:
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Step-by-step explanation:
Answer:
-<u>One Equation</u>: is set equal to a variable
Example:
y = 2x + 1
x + 3y = -12
You already have y, plug it back into x + 3y = -12
x + 3(2x + 1) = -12
x + 6x + 3 = -12
7x + 3 = -12
(Subtract 3 from each side)
7x = -15
(Divide by 7)
x = - 2.14
-<u>No Equation</u>: is set equal to a variable
Example:
2x + y = 10
4× + 2y = -3
Subtract 2x from each side of 2x + y = 10, you should get y= -2x + 10. Now that you have found y, substitute y into 4x+ 2y = -3.
4x + 2(-2x + 10) = -3
4x + -4x + 20 = -3
(Subtract 20 from each side)
4x + -4x = -23
(Add 4x and -4x)
0 = -23
No Solution
<u>-Both</u><u> </u><u>Equations</u>: are set equal to a variable
Example:
y = x + 5
y = -x + 3
(you already have y so plug it into the other equation to solve for x)
-x + 3 = x + 5
(Add -x on both sides)
3 = 2x + 5
(subtract 5 from both sides)
-2 = 2x
(Divide by 2 on each side)
x = -1
I hope this helped!
The altitude to the hypotenuse of a right triangle is the mean proportional between the segments into which it divides the hypotenuse ⇒<span>
</span>altitude = √(9*3) = √27
<span>By the Pythagorean theorem:
y = </span>√(9² + (√27)²) = √(81+27) = √108 = 6√3 ← answer
Answer:
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Step-by-step explanation:
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