15% of £70= £10.5
Expenditure =£24+£10.5=£34.5
Net amount raised =gross amount - Expenditure
=£70-£34.5=£35.5
Null: the mean amount of peanut butter in a jar is equal to 32 oz.
alternative: the mean amount of peanut butter in a Jar is less than 32oz.
type 1 error is is rejecting the null when it is actually true. this means that we would say that the mean amount of peanut butter is not equal to 32 when it actually is.
type 2 error is failing to reject the null when it is actually false. this means that we would say the mean amount of peanut butter is equal to 32 when in reality it is less.
Answer:
See below.
Step-by-step explanation:
The figure is a cone. The formula for the volume of a cone is:

The radius is 4.8 and the height is 2.9. Substitute:

Use a calculator:

And we're done!
Answer:
y = -6, x =2
Step-by-step explanation:
To solve by elimination, you have to line both equations up together. Then, you multiply both equations until one variable is removed.
2x+y = -2
5x + 3y = - 8
There are many different ways to solve an elimination problem, but generally you should look for the simplest route. Here, I would multiply the top equation by -3.
-6x -3y = 6
5x +3y = -8
Imagine you are adding the two equations together. You end up with
-x = -2
Then solve for x. In this situation, it is fairly simple. Take out a factor of -1.
x = 2
Finally, choose one of your beginning equations and plug your new-found x value back into the equation.
2(2) +y = -2
4 + y = -2
y = -6
First, we need to solve the differential equation.

This a separable ODE. We can rewrite it like this:

Now we integrate both sides.

We get:

When we solve for y we get our solution:

To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:

When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.