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Reil [10]
3 years ago
12

PLEASE HELP! THANK YOU! :D

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
6 0
I think it’s C. Sorry if I’m incorrect
nlexa [21]3 years ago
6 0
I feel like it’s c too
You might be interested in
I need some help with this<br><br>​
dalvyx [7]

\pink{\underline{{\boxed{\bf{QUESTION: }}}}}

-6(x+4) = _____

\pink{\underline{{\boxed{\bf{OPTIONS:}}}}}

  • 6x - 4❌
  • -6x + 4❌
  • -6x - 24✔️
  • 6x + 24❌

\pink{\underline{{\boxed{\bf{ ANSWER: }}}}}

-6(x+4) = <u>-6x - 24</u>

<h3>Hope It's helped! :)</h3>
4 0
2 years ago
Solve the right triangle : A=22°, c=8
coldgirl [10]

hope it helps you!!!!!!!!!!!!

8 0
3 years ago
PLEASE HELP :'))
andreev551 [17]

Answer:

D) 54 cm

Step-by-step explanation:

We can use the Centroid Theorem to solve this problem, which states that the centroid of a triangle is \frac{2}{3} of the distance from each of the triangle's vertices to the midpoint of the opposite side.

Therefore, R is \frac{2}{3} of the distance from U to V, since the latter is the midpoint of the side opposite to U. We know this because R belongs to UV, so R must be QS's midpoint due to the fact that by definition, the centroid of a triangle is the intersection of a triangle's three medians (segments which connect a vertex of a triangle to the midpoint of the side opposite to it).

We can then write the following equation:

VR=\frac{1}{3} UV

Substituting VR = 18 into the equation gives us:

18=\frac{1}{3} UV

Solving for UV, we get:

18=\frac{1}{3} UV

3 *18=3*\frac{1}{3}UV (Multiply both sides of the equation by 3 to get rid of UV's coefficient)

54=UV (Simplify)

UV=54 (Symmetric Property of Equality)

Therefore, the answer is D. Hope this helps!

7 0
2 years ago
State whether the lines are parallel, perpendicular,or neither.
cluponka [151]

Answer:

Please check the explanation.

Step-by-step explanation:

  • Two lines are parallel if their slopes are equal.
  • Two lines are perpendicular if the product of their slope is -1

We also know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept

Given the lines

1)

  • y = 6х - 3

Comparing with y=mx+b, the slope of y = 6х - 3:

m₁=6  

  • y = - 1/6x + 7

Comparing with y=mx+b, the slope of y = - 1/6x + 7:

m₂=-1/6

As

m₁ × m₂ = -1

6 ×  - 1/6 = -1

-1 = -1

Thus, the lines y = 6х - 3 and y = - 1/6x + 7 are perpendicular.

2)

  • y = 3x + 2

Comparing with y=mx+b, the slope of y = 3x + 2:

m₁=3  

  • 2y = 6x - 6

simplifying to write in slope-intercept form

y=3x-3

Comparing with y=mx+b, the slope of y=3x-3:

m₂=3

As the slopes of y = 3x + 2 and 2y = 6x - 6 are equal.

i.e. m₁ = m₂ → 3 = 3

Thus, the lines y = 3x + 2 and 2y = 6x - 6 are paralle.

3)

  • 8x - 2y = 3

simplifying to write in slope-intercept form

y = 4x - 3/2

Comparing with y=mx+b, the slope of y = 4x - 3/2:

m₁=4  

  • x + 4y = - 1

simplifying to write in slope-intercept form

y=-1/4x-1/4

Comparing with y=mx+b, the slope of y=-1/4x-1/4:

m₂=-1/4

As

m₁ × m₂ = -1

4 ×  - 1/4 = -1

-1 = -1

Thus, the lines 8x - 2y = 3 and x + 4y = - 1 are perpendicular.

4)

  • 3x+2y = 5

simplifying to write in slope-intercept form

y = -3/2x + 5/2

Comparing with y=mx+b, the slope of y = -3/2x + 5/2:

m₁=-3/2  

  • 3y + 2x = - 3

simplifying to write in slope-intercept form

y = -2/3x - 1

Comparing with y=mx+b, the slope of y = -2/3x - 1:

m₂=-2/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

5)

  • y - 5 = 6x

simplifying to write in slope-intercept form

y=6x+5

Comparing with y=mx+b, the slope of y=6x+5:

m₁=6  

  • y - 6x = - 1

simplifying to write in slope-intercept form

y=6x-1

Comparing with y=mx+b, the slope of y=6x-1:

m₂=6

As the slopes of y - 5 = 6x and y - 6x = -1 are equal.

i.e. m₁ = m₂ → 6 = 6

Thus, the lines y - 5 = 6x and y - 6x = -1 are paralle.

6)

  • y = 3х + 9

Comparing with y=mx+b, the slope of y = 3х + 9:

m₁=3  

  • y = -1/3x - 4

Comparing with y=mx+b, the slope of y =  1/3x - 4:

m₂=1/3

As m₁ and m₂ are neither equal nor their product is -1, hence the lines neither perpendicular nor parallel.

8 0
2 years ago
if two angles are complementary then the sum of their measure is 90. if the sum of the measures of two angles is 90 then both of
Tju [1.3M]
Yes, both angles are acute because all complementary angles are acute.
6 0
2 years ago
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