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4 years ago

What is the probability that a 5-digit integer chosen at random is divisible by 5??

1 answer:

7 0

This is sort of a guess, but it makes sense in my head. I'm going to say 2/10, because for a number to be divisible by 5 it has to either end in a 5 or a 0, and those are 2 options out of 10. You could simplify 2/10 down to 1/5, which would be the final answer. I'm not sure, but this is the best I can offer. I hope this helps!

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11111nata11111 [884]

Answer:

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3 years ago

Read 2 more answers

Z^m-n (z^m+ z^m+n + z^n)

rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:

(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

1=(−1)2n=[(−1)n]2 which is always true, no matter what n is

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3 years ago

6x – 3y = -33<br> - 6x + 5y = 31

Readme [11.4K]

Answer:

check online for more information

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2 years ago

Simplify (4^7/5^2)^3

Nuetrik [128]

Answer:

4²¹/5⁶ or 4398046511104/15625

Step-by-step explanation:

Remember, when raising a term with an exponent to some power, you must multiply the powers.

$(\frac{4^{7} }{5^{2} })^{3} \\\\ = (\frac{(4^{7})^{3} }{(5^{2})^{3} }) \\\\= \frac{4^{7 * 3} }{5^{2* 3} } \\\\= \frac{4^{21} }{5^{6} } \\\\=\frac{4398046511104}{15625}$

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3 years ago

Read 2 more answers

Taylor surveys students in one grade level who own at least one pet. She finds that 50% of the students surveyed own 2 pets, 3 s

Llana [10]

First, we need to work out the total number of students who were being surveyed.

We know that half of the students has two pets. The rest of the students make up the other half. So, we have 3 students + 2 students + 8 students = 13 students that make half of the sample population

That means total number of students being surveyed is 13+13=26 students

Then we work out the probability
P(One pet) = 8/26 = 4/13
P(Two pets) = 1/2
P(Three pets) = 3/26
P( Four pets) = 2/26 = 1/13

The probability distribution is shown in the table below. Let $x$ be the number of pets and $P(X=x)$ is the probability of owning the number of pets

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4 years ago

Read 2 more answers