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kicyunya [14]
3 years ago
10

What is the square root of 16 X ^36

Mathematics
2 answers:
gayaneshka [121]3 years ago
6 0
2/3 decimal form is 0.6+
ruslelena [56]3 years ago
5 0

Answer:

\sqrt{16 \times 36 }  \\  = 4 \times 6 \\  = 24

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How would I graph y=3x???
Sever21 [200]

Answer:

Go to desmos

Step-by-step explanation:

3 0
3 years ago
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the temperature in an experiment is increased at a constant rate over a period of time until the temperature reaches 0 degrees c
dsp73

Answer:

x = 28 (So it takes 28 hours for the temperature to reach 0°C.)

y = -70 (So the temperature when the experiment begins is −70°C.)

Step-by-step explanation:

To find the the x value, you remove the y value or replace it with 0.

0 = 5/2x - 70

Next you move the variable.

70 (2/5) = x           (multiply 70 by 2 to get 140 and divide that by 5)

And now you simplify to get:

28

To find the y value, you remove the x value or replace it with 0.

y =  0 - 70

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3 years ago
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3 times the square root of 18
AnnyKZ [126]

Answer:

9 square root of 2 or 12.73

7 0
3 years ago
Please help!!!!!!!!!!
topjm [15]
Ah yes, good ol’ Pythagorean’s theorem.

The hypotenuse is the opposite of the 90 degree angle, the longest side of the triangle.

The legs are opposite of the acute angles

Formula: a^2 + b^2 = c^2

2:

Let’s plug in some values

(6)^2 + (3)^2 = c^2

C = 6.7

The side will be 6.7 units

3)

Let’s plug in some values

(13.3)^2 = (9.7)^2 + (b)^2

(13.3)^2 - (9.7)^2 = b^2

176.89 - 94.09 = b^2

b = 9.1

The side will be 9.1 units
3 0
3 years ago
In a paragraph, explain whether or not all geometric sequences are exponential functions.
ANTONII [103]

Answer:

In a short terms, if you have geometric sequences are most likely(99% sure) to be exponential functions because aromatic functions are the opposite of exponential. Aromatic function are used for linear equation, graphs, and functions while exponential functions will be used for exponential equations, graphs, and functions. So yes, all geometric sequences are in fact exponential functions.

Hope this is helpful.

8 0
3 years ago
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