N^2 - 4n + n^2 + 8n = n^2 - 13n + n^2 + n + 16
-4n + 8n = -13n + n + 16
-4n = -12n + 16
4n + 12n = 16
16 = 16
n = 1
<h3>
Answer: There is only one answer and it is choice B</h3><h3>Angle 1 and angle 4 are alternate interior angles</h3>
========================================================
Explanation
- A. This is false because it should be angle 4 + angle 5 = 180 without the angle 6. Adding on angle 6 results in some angle larger than 180. Note how angle 5 = (angle 3)+(angle 6).
- B. This is true and useful to showing that the three angles of a triangle add to 180 degrees. This is because you'll use the fact that angles 4, 5 and 6 combine to 180 degrees.
- C. While this is a true statement by the exterior angle theorem, it is not useful to the proof. It is better to state that angle 2 and angle 6 are congruent because they are alternate interior angles.
- D. Like choice C, it is true but not useful. It's better to say that angle 1 is congruent to angle 4. See choice B above.
Note how it's not enough for a statement to be true. It also needs to be relevant or useful to the context at hand. A more simpler example of this could be stating that x+x = 2x.
Yep, this one seems sneaky and confusing. But it's not so bad if you remember the things you learned about parallel lines. (It can't be too tough ... I learned them
in 1954 and I still know how to use them.)
Look at the picture. Line ' l ' is parallel to line ' m ', and the horizontal line on the bottom (which is not labeled) is a transversal that cuts the parallel lines.
Did you learn that interior angles on the same side of the transversal are equal ?
I'm sure you did, although it may have a new name nowadays.
Anyway, with the help of that 'tool', angle-'B' and angle-'D' are equal. So . . .
(angle-A + angle-B) = 120
angle-B = 65
angle-A = 120 - 65 = <u>55 degrees</u>.