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IrinaVladis [17]
3 years ago
11

help please! what is the equation of the line described below written in slope-intercept form? the line passing through point (4

, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 a) y = -x 1 b) y = x - 1 c) y = 2x 1
Mathematics
2 answers:
Lunna [17]3 years ago
8 0
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 2x - y - 7 = 0
y = 2x - 7; Hence m1 = 2
m2 = -1/2
Required equation y - y1 = m2(x - x1)
y - (-1) = -1/2(x - 4)
y + 1 = -1/2x + 2
y = -1/2x + 2 - 1
y = -1/2x + 1
Vlad1618 [11]3 years ago
5 0

Answer:

y= -1/2x + 1

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The midpoint of a segment divides the segment into equal halves

The other endpoint is 1- 5i

<h3>How to determine the missing endpoint </h3>

The coordinates are given as:

Point 1: 7 + i

Midpoint: 3 - 2i

Represent the other endpoint with x.

So, we have:

2 * Midpoint = Point 1 + x

This gives

2 * (3 - 2i) =7 + i + x

6 - 4i =7 + i + x

Collect like terms

x = 6 -7- 4i -i

Evaluate the like terms

x = 1- 5i

Hence, the other endpoint is 1- 5i

Read more about midpoints ta:

brainly.com/question/9635025

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1 year ago
Tonisha has a lemonade stand. She has 31 dollars in expenses and wants to make at least 66 dollars per day. If x represents the
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Answer:

x-31(Greater than or equal to)66 -->x(greater than or equal to)97

Step-by-step explanation:

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3 years ago
Help, please I can't answer it
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Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
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Step-by-step explanation:

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The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
2 years ago
The weight W of an aluminum flatboat varies directly with the length L of the boat. If a 6​-foot boat weighs 102 ​pounds, then w
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