The input value can always be any number
2 because 5 times 2 is 10 and 2 plus 7 is 9
Answer:
3.78
Step-by-step explanation:
How you do this problem is by simply multiplying 14% by 27. You have to remember that 14% is equivalent to 0.14, so you have to do 0.14 * 27 and you will get 3.78.
Answer:
2x² + 7x + 6
Step-by-step explanation:
To solve this polynomial, you need to distribute/multiply, (x+2) with (2x+3).
You would first multiply (x) with 2x and 3. This would give you 2x² and 3x. You would then multiply 2 with 2x and 3. This would give you 4x and 6. You then add the like-terms, which are 3x and 4x, which gives you 7x. This would give you your final expression of 2x² +7x + 6.
(x+2)(2x+3)
2x²+ 3x + 4x + 6
2x² +7x + 6
Let the first number of the five we are looking for equal n.
Because the numbers are consecutive, the next four can be expressed as (n+1), (n+2), (n+3) and (n+4).
Our series of 5 numbers is therefore n,(n+1),(n+2),(n+3),(n+4).
We are told the sum of the squares of the first 3 is equal to the sum of the squares of the last 2 therefore:
n² + (n+1)² + (n+2)² = (n+3)² + (n+4)²
expand all the brackets to give
n² + n² + 2n + 1 + n² + 4n + 4 = n² + 6n + 9 + n² + 8n + 16
3n²+6n+5 = 2n²+14n+25
n²-8n-20=0
factorising this gives us
(n+2)(n-10) = 0 so the solutions are n=10 and n=-2
That means that n,(n+1),(n+2),(n+3),(n+4) could be [-2, -1, 0, 1 and 2] or [10, 11, 12, 13 and 14].
Since the question asks for whole numbers, and negative numbers are not classed as whole numbers, the numbers we want must be 10, 11, 12, 13 and 14.
You can check this on a calculator by doing 10² + 11² + 12² (=365) and 13² + 14² (=365).
