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mylen [45]
3 years ago
14

Guys help me 3(x−4)≥−2x+3

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Answer:

sensya na bobo den ako e✌

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I need to know this plz answer quick thanks - dely
Tpy6a [65]
120/12=x
120/12=10
Then answer to this problem is B
7 0
4 years ago
which of the following numbers which of the following numbers when added to it perfect squares is 240 ​
Katena32 [7]

Answer:

first of all square mean two number or double so if we multiple 15×15=225 and if we multiply 16×16=256 mean the number 240 lies between them what about number 15.5 lets try now 15.5×15.5=240.25 if you want to make sure so just take a square root of this number

\sqrt{240.25}  = 15.5

so 240 is product of (15.5)² note number after point is negligible

4 0
3 years ago
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Whats the greatest common factor of 21,24,27
klasskru [66]
<span>The Greatest Common Factor (GCF) is: 3</span>
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4 years ago
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PLZZZZZZZZZZZZZZZXX HELP MEEEEEE
ankoles [38]

Answer:

-5/3

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3 0
3 years ago
The mean weight of boxes shipped by a company is 12 lbs., with a standard deviation of 4 lbs. Assume weight of boxes follows Nor
777dan777 [17]

Answer:

0.89% probability that a palette of 10 boxes will exceed that limit (150 lbs.)

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 12, \sigma = 4, n = 10, s = \frac{4}{\sqrt{10}} = 1.2649

1. What’s the probability that a palette of 10 boxes will exceed that limit (150 lbs.)? a. HINT: Prob (total weight of a sample of 10 boxes >150 lbs.) = Prob (the sample mean weight ( y hat ) > 15 lbs.)

This is 1 subtracted by the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{15 - 12}{1.2649}

Z = 2.37

Z = 2.37 has a pvalue of 0.9911

1 - 0.9911 = 0.0089

0.89% probability that a palette of 10 boxes will exceed that limit (150 lbs.)

6 0
4 years ago
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