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mylen [45]
3 years ago
14

Guys help me 3(x−4)≥−2x+3

Mathematics
1 answer:
Scrat [10]3 years ago
5 0

Answer:

sensya na bobo den ako e✌

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The solution to the inequality -3x +8 < 11 is
galina1969 [7]

Answer:

x > -1

Step-by-step explanation:

-3x +8 < 11

Subtract 8 from each side

-3x +8-8 < 11-8

-3x < 3

Divide each side by -3, remembering to flip the inequality

-3x/-3 > 3/-3

x > -1

5 0
3 years ago
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P1(-5,-7) and P2(-3,-3)
svetoff [14.1K]

So, P1P2 = \sqrt{ (-3 + 5)^{2}  +   (-3 + 3)^{2} } = \sqrt{  2^{2} +  0^{2} } = 2 ;

3 0
4 years ago
Each page of a photo album holds three rows of four square photos. The area of each photo is 25 cm². There is 2 cm space between
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<span>32 cm wide by 25 cm tall. Since each photo is square and has an area of 25 cm², that means that the length of each edge of the photos is 5 cm. So the length of a page (2 border gaps + 4 photos + 3 spacing gaps) is 2*3 + 4*5 + 3*2 = 32 cm The height of a page (2 border gaps + 3 photos + 2 spacing gaps) is 2*3 + 3*5 + 2*2 = 25 cm So the page size is 32 cm x 25 cm</span>
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3 years ago
A tree broke due to storm at a point but did not get separate . its tops touched the ground at a distance of 10 m from its base
kirill [66]
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7 0
4 years ago
A group of freshmen at a local university consider joining the equestrian team. Thirty‑five percent of students choose Western r
lesantik [10]

Answer:

a) Option D) 0.75

b) Option D) 0.3

Step-by-step explanation:

We are given the following in the question:

Percentage of students who choose Western riding = 35%

P(w) = 0.35

Percentage of students who choose dressage= 45%

P(d) = 0.45

Percentage of students who choose jumping = 50%

P(j) = 0.50

Percentage of students who choose both dressage and jumping = 20%

P(d \cap j) = 0.20

Percentage of students who choose Western and dressage = 10%

P(w \cap d) = 0.10

Percentage of students who choose Western and jumping = 0%

P(w \cap j) = 0

Thus, we can say

P(w \cap j \cap d) = 0

Formula:

P(A \cup B) = P(A) + P(B) - P(A \cap B)

a) P(student chooses dressage or jumping)

P(d \cup j) = P(d) + P(j) -p(d \cap j)\\= 0.45 + 0.50-0.20 = 0.75

b) P(student chooses neither dressage nor Western riding)

= 1 - P(d \cup w)\\= 1 - (P(d) + P(w) - P(d \cap w))\\= 1 - (0.45 + 0.35 - 0.10)= 0.3

5 0
4 years ago
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