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loris [4]
3 years ago
10

Andrea is told that the means of two groups in a study were statistically significant. She knows the means and standard deviatio

ns of the two groups and is interested in calculating an estimate of effect size. Given this information, which effect size estimate should she calculate
Mathematics
1 answer:
salantis [7]3 years ago
5 0

Answer:

Cohen's D

Step-by-step explanation:

Cohen's D is a statistic that measures effect size. It shows standardised difference between 2 means.

Effect size is defined as how large the effect of a something is or its magnitude.

Cohen's D works effectively when the sample is >50 (that is for large samples). However a correction factor can be used to make results from small samples more accurate

The formular for Cohen's D is:

D = (mean1 - mean2) ÷ (√({standard deviation1}^2 + {standard deviation 2}^2)/2)

This is the most appropriate method in the given scenario

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One inch of board is left
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the further subtract the 24 inches from the three 8 inches pieces you get 31-30
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What are the coefficients in 9/3+6+9a​
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cuz it has a variable by it

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2 years ago
Which interval is the solution set to 0.35x - 4.8 < 5.2 -0.9x?
8_murik_8 [283]

Answer:  (-\infty, 8)

Step-by-step explanation:

Given the following inequality:

0.35x - 4.8 < 5.2 -0.9x

You need to solve for "x" in order to find the solution.

The steps are:

1. Add 0.9x to both sides of the inequality:

0.35x - 4.8+0.9x < 5.2 -0.9x+0.9x\\\\1.25x-4.8

2. Add 4.8 to both sides:

1.25x-4.8+4.8

3. Divide both sides by 1.25:

\frac{1.25x}{1.25}

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The solution in Interval notation is:

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To calculate the cost of painting his silo, a farmer must find its height. The farmer uses a cardboard square to line up the top
tankabanditka [31]

Answer:

Height of the silo = 18 feet.

Step-by-step explanation:

From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.

Farmer is standing at 8 ft distance from the silo.

From triangle AEC,

tan(∠CAE) = \frac{CE}{AE}

                 = \frac{5}{8}

m(∠CAE) = tan^{-1}(\frac{5}{8})

               = 32°

m∠BAE = 90° - 32° = 58°

From the triangle ABE,

tan58° = \frac{BE}{AE}

BE = 8tan58°

BE = 12.8 ft

Total height of the silo = BE + EC

                                         = 12.8 + 5

                                         = 17.8

                                         ≈ 18 ft          

Therefore, total height of the silo is 18 ft.

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3 years ago
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