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Gennadij [26K]
3 years ago
13

Shanelle already has $137 from babysitting. She needs at least $625 for a new tablet. Which inequality best represents this scen

ario?
t – 137 > 625
t + 137 ≥ 625
t + 137 < 625
t – 137 ≤ 625
Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

t + 137 ≥ 625

Step-by-step explanation:

Shanelle already have in her possession the sum of $137 from babysitting.  She requires at least $625 for a new tablet. t is the remaining amount she needs to get the new tablet.

She already has $137 and to get the tablet she needs at least $625 . This means she needs nothing less than or equal to $625 to get the tablet.  Recall t is the remaining amount needed to add to what she has to be able to reach the least amount required to purchase a tablet. Therefore , the sum of t and the amount of money already in her possession should be equal to or greater than $625.

To get the new tablet,

t + 137 ≥ 625

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What steps should be used to find 55% of 300? Check<br> all that apply.<br> ger
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A professor said 4/5 of his students passed the final examination. If 60 students took the exam, how many passed?
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
aleksandr82 [10.1K]

Hello, I Am BrotherEye

Answer:

Median = 46.5

Minimum = 32

Maximum = 62

Lower quartile = 38

Upper quartile = 59

Step-by-step explanation:

Before we can proceed to solving any of these, it is best you arrange your data first from least to greatest

32  34  37  39  41  45  48  53  58  60  61  62

First we have the median. The Median is the middle value. In this case we an even number of data, which is 12 data points. The middle value of the data would be found in between the 6th and 7th data point:

45 and 48

To get the middle value, you need to solve for the value that is in the middle of 45 and 48 by getting the sum of both numbers and dividing it by two.

45 + 48 = 93

93 ÷ 2 = 46.5

The minimum and maximum value is merely the least and greatest number.

Here we have:

Minimum = 32

Maximum = 62

To get the lower and upper quartiles, just remember that quartiles divide the data into 4 equal parts. All you need to do is find the value that is in between each quarters of the data:

           Q1 (Lower)  Q2(Median) Q3(Upper)

32  34  37 |  39  41  45 | 48  53  58 | 60  61  62

Like the median, we will find the value that comes in between each quarter.

Q1

37 + 39 = 76

76 ÷ 2 = 38

Lower quartile = 38

Q3:

58 + 60 = 118

118 ÷ 2 = 59

Upper quartile = 59

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