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2 years ago

Write 25.59 in scientific notation

Mathematics

2 answers:

ad-work [718]2 years ago

7 0

Answer:

2.559 × 10 to the 1st power

Step-by-step explanation:

using a SNC

motikmotik2 years ago

4 0

Answer:

2.559 * 10^1

Step-by-step explanation:

Rules of scientific notation (that I always remember)

- the number must be between 1 and 9

- if number gets smaller, exponent gets bigger; if number gets bigger, exponents gets smaller

25.59 is bigger than 9 so we move the decimal one place value to the left

and the number gets smaller meaning the exponent increases

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Andreyy89

Answer:

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Step-by-step explanation:

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3 years ago

How to integrate 1/(1-y)^2

Akimi4 [234]

If you're using the app, try seeing this answer through your browser: brainly.com/question/866966

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy}\\\\\\ =\mathsf{\displaystyle\int\!\dfrac{-1}{(1-y)^2}\cdot (-1)\,dy}\\\\\\ =\mathsf{\displaystyle- \int\!(1-y)^{-2}\cdot (-1)\,dy\qquad\quad(i)}$

Substitution:

$\begin{array}{lcl} \mathsf{1-y=u}&\quad\Rightarrow\quad&\mathsf{y=1-u}\\\\ &&\mathsf{dy=-1\,du} \end{array}$

So the integral $\mathsf{(i)}$ becomes

$=\mathsf{\displaystyle -\int\! u^{-2}\,du}\\\\\\ =\mathsf{-\,\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\ =\mathsf{-\,\dfrac{u^{-1}}{-1}+C}\\\\\\ =\mathsf{u^{-1}+C}\\\\\\ =\mathsf{\dfrac{1}{u}+C}$

$=\mathsf{\dfrac{1}{1-y}+C}\\\\\\\ \therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\!\dfrac{1}{(1-y)^2}\,dy=\dfrac{1}{1-y}+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: indefinite integral fraction rational substitution power differential calculus

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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