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3 years ago

6

On a certain day the exchange rate was 60 u.s dollars 50 euro. How many US dollars were 70 euro worth that day? Show that your a

wnser is reasonable

1 answer:

gayaneshka [121]3 years ago

8 0

This is what I got:

60/50 = X/70
70x60/59 = X
X = 84

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Pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Fiesta28 [93]

Answer:

bottom right corner

Step-by-step explanation:

3 0

3 years ago

Each statement describes a transformation of the graph of y = lnx. Which statement correctly describes the graph of y = ln(x - 7

vodomira [7]

Hello!

The parent function, y = ln(x), has a vertical and horizontal translation.

y = ln(x - h) + k | In this equation, h is the vertical shift, and k is the horizontal shift.

If ln(x - k), then the graph is translated right k units.

If ln(x + k), then the graph is translated left k units.

If ln(x) + h, then the graph is translated up h units.

If ln(x) - h, then the graph is translated down h units.

Therefore, the graph of y = ln(x - 7) + 3 is translated 3 units up and 7 units to the right, which is choice D.

7 0

4 years ago

disa [49]

Answer:

452.39 mm^2

Step-by-step explanation:

Area of a circle = $\pi$ r^2

Here r = 12mm

Therefore, Area= $\pi$ x 12^2 = 452.389342...

Round to required degree of accuracy = 452.39mm^2

Hope this helps

8 0

3 years ago

The points A BC :(2, 2,1), :(1,1,3), :(2,0,5) − are the vertices of a right triangle. The radius of the sphere with center at th

ElenaW [278]

Answer:

r=1

Step-by-step explanation:

First we need to know the length of each side of the triangle, so we use the formula of the vector modulus:

$|AB|= \sqrt{(b_{1}-a_{1})^{2}+(b_{2}-a_{2})^{2}+(b_{3}-a_{3})^{2}$

By doing so, we find:

$|AB|=\sqrt {6}\\|BC|=\sqrt {6}\\|AC|=2\sqrt {5}$

With this we know that the triangle is not right, but, we assume the longest side as the hypotenuse of the problem.

As we have two equal sides, we know that the line between point |AB| and the center of the hypotenuse is perpendicular, therefore, we can calculate it using Pythagoras theorem:

$|BC|^{2}=r^{2}+(\frac{|AC|}{2})^{2}\\\\r^{2}=|BC|^{2}-(\frac{|AC|}{2})^{2}\\\\r^{2}=(\sqrt{6})^{2}- (\frac{2\sqrt{5}}{2})^{2}\\\\r^{2}=6-5=1\\r=1$

4 0

3 years ago

Let a and b be non-zero integers. Which of the following is always true about the ratio ?

mezya [45]

C. It is always a rational number. You cannot determine its sign without knowing the values of a and b.

8 0

4 years ago

Read 2 more answers