According to the probles represented above, there is addition of two angles which makes it totally clear. I am pretty sure that the answer with the actual reason of this task is the second option <span>B. Angle Addition Postulate, as you can see a couple of new angles in there :)
Regards!</span>
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Distribute 5 using the Distributive Property:
5(x+24)
Multiply 5 by x:
5x
Multiply 5 by 24:
120
Now, add the products:
5x+120 (Answer)
Hope it helps! Enjoy your day :)
~Just a determined teen
Circumference = 2 * pi * r, where r is the radius
For this circle, the circumference is 11pi, so 11pi=2*pi*radius. Divide both sides by 2pi and you get r is = to 5.5 inches.
Area of a circle is pi*r^2. Since we just saw that r = 5.5 inches, the circle has an area of 5.5 inches * 5.5 inches * pi or 30.25 pi inches squared.
Answer:
B) (0, 0)
Step-by-step explanation:
It is where the two figures intersect on the graph!
<u><em>Hope this Helps!! :))</em></u>
