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astraxan [27]
4 years ago
9

A bookstore decides to divide its space into three sections:nonfiction books, novels, and stationary. The bookstore wants to dev

ote one fifth of its space to stationary. If the total area of the bookstore is 288 square feet, and the stationary section will be 12 feet long, how wide will the stationary section be
Mathematics
1 answer:
devlian [24]4 years ago
8 0

Answer:

4.8

Step-by-step explanation:

First we divide the total rea by 5 to find the total space allotted to the stationary.

288/5 = 57.6

Next we divide by 12 to find the width

57.6/12 = 4.8

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Which expression is equivalent to sqrt48x^5 if x>0
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lora16 [44]

Given:

The total number of people are T = 267.

Explanation:

(a)

Determine the total number of teens.

\begin{gathered} t=39+43+25 \\ =107 \end{gathered}

The probability for the person to be a teen is,

\begin{gathered} P(t)=\frac{107}{267} \\ =0.4007 \end{gathered}

(b)

Determine the number of people like the vanilla.

\begin{gathered} v=22+43+44 \\ =109 \end{gathered}

Determine the propability for the person selected likes the Vanilla.

\begin{gathered} P(v)=\frac{109}{267} \\ =0.4082 \end{gathered}

(c)

Determine the number of people that are teen or likes the vanailla.

\begin{gathered} v\text{ OR t=}22+43+44+39+25 \\ =173 \end{gathered}

Determine the probability for a selected person is a teen or like the vanilla.

\begin{gathered} P\text{ (v or t)=}\frac{173}{267} \\ =0.6479 \end{gathered}

(d)

The number of person that is teen and likes strawberry best are 25.

Determine the probability for selected person is teen and likes strawberry best.

\begin{gathered} P\text{ (t and s)=}\frac{25}{267} \\ =0.0936 \end{gathered}

(e)

Determine the number of persons that are children.

\begin{gathered} C=21+22+9 \\ =52 \end{gathered}

Determine the number person that are children and likes strawberry best.

\text{ C and s=}9

So probability for the person likes the strawbwerry given that person is children is,

\begin{gathered} P\text{ (s|C)=}\frac{P\text{ (s and c)}}{P\text{ (c)}} \\ =\frac{\frac{9}{267}}{\frac{52}{267}} \\ =\frac{9}{52} \\ \approx0.1731 \end{gathered}

(f)

The number of persons who likes the strawberry best is,

\begin{gathered} s=9+25+25 \\ =62 \end{gathered}

Determine the probability for person is teen given that person likes strawberry best.

\begin{gathered} P\text{ (}t|s\text{)}=\frac{P\text{ (t and s)}}{P(s)} \\ =\frac{\frac{25}{267}}{\frac{62}{267}} \\ =\frac{25}{62} \\ =0.4032 \end{gathered}

Answer:

Is a teen: 0.4007

Likes vanilla the best: 0.4082

Is a teen or likes the Vanilla the best: 0.6479

Is a teen and likes the strawberry best: 0.0936

Likes strawberry the best GIVEN the person is child: 0.1732

Is a teen GIVEN that person likes the strawberry best: 0.4032

8 0
1 year ago
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