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3 years ago

Find the LCm for the pair of natural numbers 112,96

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

Answer:

672.

Step-by-step explanation:

First find the prime factors:

112 = 2*2*2*2*7

96 = 2*2*2*2*2*3

There are 4 pairs of duplicate 2 's in the factors, so the LCM = 2*2*2*2*2*3*7

= 672 (answer).

Note: the duplicates only appear once in the calculation of the LCM.

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Over the past 10 years, five mutual funds all had the same mean rate of return. The standard deviations for each of the five mut

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Answer:

C. Vanity

Step-by-step explanation:

As each of the five mutual funds have same mean rate of return, we go for standard deviation of the rate of return to judge which one has the least consistency among the five.

We know that standard deviation is a measure for variation in a data-set. So more the standard deviation of a data, more is the variation in the data-set and less is the consistency of the data-set.

Here, among the given five mutual fund, we see that "Vanity" has the highest standard deviation (9.4%) in rate of return. So the mutual fund "Vanity" has the least consistency.

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What is the area of 20 and 15

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What values do x and y have if /x/ =16 /y/=16 and when x and y are combined they eqaul zero? Explain your reasoning

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They have opposite signs. if x=16 then y should be -16 for their sum to be zero.

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The width of a rectangle is 6 cm less than its length. If its perimeter is 80 cm then its lengths (in cm) and area (in cm²) are

mr_godi [17]

Start by stating the given info as mathematical expressions:

1. "<span>The width of a rectangle is 6 cm less than its length."
$w=l-6$

2. "I</span><span>ts perimeter is 80 cm."
$P=80$

Using the formula for perimeter ( $P=2l+2w$ ) we can show:
$80=2l+2w$ .

We now have 2 equations in 2 unknowns and can solve by substitution:
</span> $80=2l+2w$
$80=2l+2(l-6)$
$80=2l+2l-12)$
$92=4l$
$l=23$

The length is 23cm.

Having the length w can then find the width:
$w=l-6$
$w=23-6$
$w=17$

The width is 17cm.

And finally the area:
$A=lw$
$A=(23)(17)$
$A=391$

The area is $391cm^{2}$ .

As a check we can use the known perimeter:
$80=2l+2w$
$80=2(23)+2(17)$
$80=46+34$
$80=80$ Checks true.

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3 years ago