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Trava [24]
3 years ago
14

Find the quotient.

Mathematics
2 answers:
never [62]3 years ago
5 0

Answer:

48÷3=16

Step-by-step explanation:

In the expression, 96 divided by 8 = a , the quotient a =12

. Divide 12 lizards into 6 equal groups. How many lizards are in each group?

There are2

lizards in each group.

vazorg [7]3 years ago
3 0

Answer:

1.    16

2.   6

3.    2

Step-by-step explanation:

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Which expressions are equivalent to the given expression? ​
expeople1 [14]

Answer:

It is the 2nd answer choice 4 check 5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a2 + b2 = c2, which in this iso
abruzzese [7]

Complete Question

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

a) substitute values for a and c into the original pythagorean theorem equation.

b) divide both sides of the equation by two, then determine the principal square root of both sides of the equation.

c) determine the principal square root of both sides of the equation.

d) divide both sides of the equation by 2.

Answer:

c) determine the principal square root of both sides of the equation.

Step-by-step explanation:

Pythagoras Theorem for a right angled triangles states that:

a²+ b²= c²

But for an Isosceles Triangle, where two sides of the triangle are equal, we have:

a²+ a² = c²

By combining like terms

2a² = c²

We square root both sides of the equation.

√2a² = √c

√2a² = c

The final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg = √2a² = c is Option c.

4 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!!!!!!!!!!!!
vivado [14]
Hi there ! i think is number one. or a
4 0
3 years ago
Read 2 more answers
How do I factor out a constant before factoring out a quadratic? <br>Factor completely: 3w^2-3w-90
pantera1 [17]
3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5

w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)
 

3 0
3 years ago
Create a pattern with the rule n-4
aalyn [17]
You would make a table first, the top part, just start from zero and add every time. Hope this helps
5 0
3 years ago
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