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3 years ago

Find each missing measure

Mathematics

1 answer:

Stells [14]3 years ago

5 0

Answer: x=32 y=58 z=32

Step-by-step explanation:

For x, you just have to subtract 148 form 180.

For y, you just have to subtract 90 from 148.

For z, it is a vertical angle so it is equal to x.

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Geometry problem in the picture: find the missing side and round to the nearest tenth

Vlad1618 [11]

Answer:

X= 19.9

Step-by-step explanation:

SOH CAH TOA

x is hypotenuse

Opposite is 15

Opposite & hypotenuse - sin

Sin(49) = o/h

Sin(49) = 15/h

Sin(49) x h = 15

÷Sin(49)

h = 15 ÷ Sin(49)

h=19.8751949

Hope this helps!

4 0

2 years ago

a sporting goods company can ship 6 footballs in each carton. how many cartons are needed to ship 75 footballs

Dahasolnce [82]

75 ÷ 6 = 12.5 round up to the next whole number... 13

7 0

2 years ago

Read 2 more answers

What inequality describes the weight range of a single nickel

Evgen [1.6K]

Answer:

4.806 g ≤ n ≤ 5.194 where n is the mass of a nickle.

Step-by-step explanation:

The problem tells us the weight can vary by .194 g, this means it can be up to .194 lighter and 194 heavier. Well what value is .194 lighter and .194 heavier? 4.806 and 5.194 respectively. So that means a nickle can be anywhere in that range, which tells us the inequality.

5 0

3 years ago

Solve the equation: 12+3/4x=14

Alinara [238K]

Answer:

x=2 and 2/3

Step-by-step explanation:

4 0

3 years ago

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Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$

Blizzard [7]

$\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}$

$a^{81}\equiv1^{81}\equiv1\pmod7$

$b^{91}\equiv2^{91}\pmod7$

$2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7$
$8\equiv1\pmod7$
$2\equiv2\pmod7$
$\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7$

$c^{27}\equiv6^{27}\pmod7$

$6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7$

$\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7$

6 0

2 years ago