The answer is mode as it is the only one that doesn’t need to contain numbers. The mode is the one with the most of the same thing. So in this case it’s the pizza
I hope you understand it now x
Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Answer:
Ok I’ll give a simple equation that your teacher probably won’t accept and one that your teacher will accept
Teacher accept: x-45=122
Not accept but way easier: 122+45=x
ALSO The answer to x: 167
Step-by-step explanation:
Heres the loop hole, they asked for 2 sentences but never declared the length of each sentence.
Explanation:
So we know that grace lost 45 pounds and at the end she weighs 122.
We don’t now what the beginning weight so we can make an equation like x-45=122 where x represents her before weight and the subtract 45 is when she lost that much and the final results of 122, if solved You’ll get her begginisng weight, 167.
Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
