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natima [27]
3 years ago
9

What is the slope of line p? On a coordinate plane, a straight line goes through (negative 3, negative 2), (0, 0), and (3, 2). I

NEED HELP FAST PLEASE, THANK YOU !!!!!
Mathematics
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

slope = 2/3

Step-by-step explanation:

To find the slope you use this equation:

difference in y / difference in x

so let's take two points you have given

(3,2) and (0,0)

take the difference in y which is both y coordinates so

2-0 = 2

and take the difference in x which is both x coordinates so

3-0 = 3

2/3

dlinn [17]3 years ago
5 0
To figure out the slope you would want to use this formula for 2 of the points: Y2-Y1/X2-X1.

if you followed this for (-3,-2) and (3,2), you would get 2-(-2)/3-(-3)

this would equal 4/6, which simplifies to 2/3

the slope of line p = 2/3x
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The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

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and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


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