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3 years ago

If mean is 6 wat number could be p given se t of numbers r 4,5,8,p,7,6

1 answer:

6 0

Let's solve your equation step-by-step.(4+5+8+p+7+6)/6=6Step 1: Multiply both sides by 6.(4+5+8+p+7+6)/6=6(4+5+8+p+7+6)/(6)*(6)=(6)*(6)4+5+8+p+7+6=36Step 2: Simplify both sides of the equation.p+30=36Step 3: Subtract 30 from both sides.p+30−30=36−30p=6Answer:p=6

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Svetllana [295]

Answer:

26 degrees

Step-by-step explanation:

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3 years ago

What is measurement

Hatshy [7]

Answer:

The comparision of an unknown physical quantity with a known standard quantity is measurement

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4 years ago

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Two cars simultaneously left Points A and B and headed towards each other, and met after 3 hours and 15 minutes. The distance be

ella [17]

Answer:

50 mph, 62 mph

Step-by-step explanation:

Their total speed is found from ...

speed = distance/time

speed = (364 mi)/(3.25 h) = 112 mi/h

If s is the speed of the slower car, then ...

s + (s+12) = 112 . . . . . their total speed is 112 mph

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3 years ago

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A round trip from Montreal to LA is 2,688 miles and takes an airline 9 hours and 20 minutes. Given the outbound trip is the same

Ksju [112]

Answer:

4.074 hours

Step-by-step explanation:

r =

The formula for speed = Distance × Time

Hence,

Let the outbound speed = r

return trip speed = r + 25x/100 = 125r/100 = 1.25r

Note that: 9 hours and 20 minutes = 9.167

Let t1 and t2 be the time taken to travel on way and return journey.

t1 + t2 = 9 hr 10 min = 9.167 hrs

Hence:

2688/r + 2688/1.25r = 9.167

LCM(1.25r)

(2688 × 1.25) + 2688 /1.25r= 9.167

3360 + 2688 = 9.167 × 1.25r

6048 = 11.45875r

r = 6048/11.45875

Outbound trip rl = 527.8062615904876mph

Return trip speed = r + 25x/100 = 125r/100 = 1.25r

= 1.25 ×

659.75782699mph

Time for return trip = Distance/Speed

= 2,688 miles/659.75782699mph/

= 4.0742222222 hours

Approximately = 4.074 hours

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3 years ago

A 6-foot-wide hallway is painted as shown, using equal amounts of white and black paint.

Degger [83]

we know that

The hallway is painted using equal amounts of white and black paint

To know the amount of white paint------> calculate the area of white paint

$A=5x*6=30x\ ft^{2}$

To know the amount of black paint------> calculate the area of black paint

$A=(x+1)*4*6=(24+24x)\ ft^{2}$

equate the areas

$30x=(24+24x)\\30x-24x=24\\6x=24\\x=4\ ft$

Find the length of the hallway

$5x+(4x+4)=9x+4=9*4+4=40\ ft$

therefore

the answer part a) is

The hallway is $40\ ft$ long

Part b) Can this same hallway be painted with the same pattern, but using twice as much black paint as white paint?

we know that

the amount of white paint is $30x\ ft^{2}$

if the black paint is twice that the white paint

then

amount of black paint is $2*30x=60x\ ft^{2}$

amount of black paint with the same pattern is $(24+24x)\ ft^{2}$

equate

(24+24x)\ ft^{2}=(60x)\ ft^{2}

solve for the new value of x

$24x+24=60x\\ 60x-24x=24\\ x=24/36\\x= 2/3\ ft$

Find the new length of the hallway

$5x+(4x+4)=9x+4=9*(2/3)+4=10\ ft$

therefore

the answer is

Yes, the same hallway can be painted with the same pattern, using twice as much black paint as white paint, but the hallway decreases in length

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4 years ago