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3 years ago

Is the sqrt of 102 a rational or irrational number?

Mathematics

1 answer:

lesantik [10]3 years ago

4 0

Answer:

Yes, 102 isn't a square number (1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144) so the square root of 102 will keept going forever and is irrational.

Step-by-step explanation:

basically

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Solving Percent Problems

lions [1.4K]

1.015
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2.1875
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umm what is 6.7.5%
1.6%

7 0

4 years ago

Colleen bought a suit that was discounted 25% from an orignal price of $245. Determine the sale price

Aleksandr [31]

Answer:

183.75

Step-by-step explanation:

25% of 245

3 0

3 years ago

We often deal with weighted means, in which different data values carry different weights in the calculation of the mean. For

Veseljchak [2.6K]

Answer:

a) The student's overall average for the class is 87.97.

b) He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

Step-by-step explanation:

Weighed average:

To solve this question, we find the student's weighed average, multiplying each of his grade by his weights.

Grades and weights:

Scored 82.5 on the midterm, worth 30%.

Scored 88.6 on the final exam, worth 30%.

Scored 91.6 on the homework, worth 40%.

a. On a 100-point scale, what is the student's overall average for the class?

Multiplying each grade by it's weight:

$A = 82.5*0.3 + 88.6*0.3 + 91.6*0.4 = 87.97$

The student's overall average for the class is 87.97.

b. The student was hoping to get an A in the class, which requires an overall score of 93.5 or higher. Could he have scored high enough on the final exam to get an A in the class?

Score of x on the final class, and verify that the average could be 93.5 or higher. So

$A = 82.5*0.3 + 88.6*0.3 + 0.4x$

$A \geq 93.5$

$82.5*0.3 + 88.6*0.3 + 0.4x \geq 93.5$

$0.4x \geq 93.5 - (82.5*0.3 + 88.6*0.3)$

$x \geq \frac{93.5 - (82.5*0.3 + 88.6*0.3)}{0.4}$

$x \geq 105.425$

He would need a score above 100 to get an A, which means that he could not have scored high enough on the final exam to get an A in the class.

3 0

3 years ago

The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that

Mariulka [41]

Answer: a. 0.05

b. 0.40

c. 0.85

Step-by-step explanation:

Let F= Event that a certain motorist must stop at the first signal.

S = Event that a certain motorist must stop at the second signal.

As per given,

P(F) = 0.45 , P(S) = 0.5 and P(F or S) = 0.9

a. Using general probability formula:

P(F and S) =P(F) + P(S)- P(F or S)

= 0.45+0.5-0.9

= 0.05

∴ the probability that he must stop at both signals = 0.05

b. Required probability = P(F but (not s)) = P(F) - P(F and S)

= 0.45-0.05= 0.40

∴ the probability that he must stop at the first signal but not at the second one =0.40

c. Required probability = P(exactly one)= P(F or S) - P(F and S)

= 0.9-0.05

= 0.85

∴ the probability that he must stop at exactly one signal = 0.85

7 0

3 years ago

Can you answer this math homework? Please!

pav-90 [236]

Answer:

(-4.5, 4.25) The first one.

Step-by-step explanation:

Plug in -4.5 in for x and 4.25 for y in BOTH problems. When you plug them in and they both work out for BOTH problems then its the answer.

7 0

3 years ago