Who ever makes it good I'll pay$ through PayPal I just need help by the end of today

beks73 [17]

Given:

The location of point S on a coordinate plane.

To find:

The ordered pair for the point S.

Solution:

A point is defined as (x,y), where, |x| is the distance between the point and y-axis, and |y| be the distance between the point and x-axis. Signs of coordinates depend on the quadrant.

From the given graph it is clear that,

Distance between S and y-axis = 3.5

Distance between S and x-axis = 5.5

Point S lies in 3rd quadrant, it means x- and y-coordinates are negative.

Therefore, the ordered pair of point S is (-3.5,-5.5).

8 0

2 years ago

14 2 7 3 9=10 insert symbols

Irina-Kira [14]

14×2÷7-3+9=10

Worked it out myslef and enjoy doing math.

7 0

2 years ago

Translate the following word sentence into a numerical expression: When you square five times a number, you get three more than

8090 [49]

“Square five times a number” with “a number” being x is the same as saying:

5x²

“three more than the number” is the same as saying:

3 + x

Therefore the sentence “When you square five times a number, you get three more than the number.” is the same as:

5x² = 3 + x

Hope this helps, have a great day! :)

4 0

2 years ago

Read 2 more answers

I’m a bit stuck on the second part of what y = x, can someone help me?

marissa [1.9K]

The answer should be 3, -1

4 0

2 years ago

A simple random sample of size nequals10 is obtained from a population with muequals68 and sigmaequals15. (a) What must be true

valentina_108 [34]

Answer:

(a) The distribution of the sample mean ( $\bar x$ ) is N (68, 4.74²).

(b) The value of $P(\bar X$ is 0.7642.

(c) The value of $P(\bar X\geq 69.1)$ is 0.3670.

Step-by-step explanation:

A random sample of size n = 10 is selected from a population.

Let the population be made up of the random variable X.

The mean and standard deviation of X are:

$\mu=68\\\sigma=15$

(a)

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Since the sample selected is not large, i.e. n = 10 < 30, for the distribution of the sample mean will be approximately normally distributed, the population from which the sample is selected must be normally distributed.

Then, the mean of the distribution of the sample mean is given by,

$\mu_{\bar x}=\mu=68$