Y-1=1/4(x-12)
Y-1=1/4x-3
Y=1/4x-3+1
Y=1/4x-2
Now write it in standard form ax+by+c
-1/4x+y=-2
It’s better not to have a negative in front so y-1/4x=-2
5:6 is already at it's simplest form as there are no other common factors to divide it by!
Answer:
![\huge\boxed{A=(9x^2-48x+64)ft^2}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BA%3D%289x%5E2-48x%2B64%29ft%5E2%7D)
Step-by-step explanation:
The formula of an area of a square:
![A=s^2](https://tex.z-dn.net/?f=A%3Ds%5E2)
- side of a square
We have ![s=(3x-8)ft](https://tex.z-dn.net/?f=s%3D%283x-8%29ft)
Substitute:
![A=(3x-8)^2](https://tex.z-dn.net/?f=A%3D%283x-8%29%5E2)
METHOD 1:
Use ![(a-b)^2=a^2-2ab+b^2](https://tex.z-dn.net/?f=%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2)
![A=(3x)^2-2(3x)(8)+8^2=9x^2-48x+64](https://tex.z-dn.net/?f=A%3D%283x%29%5E2-2%283x%29%288%29%2B8%5E2%3D9x%5E2-48x%2B64)
METHOD 2:
Use FOIL: ![(a+b)(c+d)=ac+ad+bc+bd](https://tex.z-dn.net/?f=%28a%2Bb%29%28c%2Bd%29%3Dac%2Bad%2Bbc%2Bbd)
![A=(3x-8)(3x-8)=(3x)(3x)+(3x)(-8)+(-8)(3x)+(-8)(-8)\\\\=9x^2-24x-24x+64=9x^2-48x+64](https://tex.z-dn.net/?f=A%3D%283x-8%29%283x-8%29%3D%283x%29%283x%29%2B%283x%29%28-8%29%2B%28-8%29%283x%29%2B%28-8%29%28-8%29%5C%5C%5C%5C%3D9x%5E2-24x-24x%2B64%3D9x%5E2-48x%2B64)
Answer:457444,5455
Step-by-step explanation:yjhjhfsetyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
Answer:
(- 3, - 4 )
Step-by-step explanation:
Under a reflection in the line y = - x
a point (x, y ) → (- y, - x ) , thus
(4, 3 ) → (- 3, - 4 )