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3 years ago

If the smallest angle of rotation for a regular polygon is 18°, how many sides does polygon have?

Mathematics

1 answer:

lora16 [44]3 years ago

4 0

Answer:

20 sides.

Step-by-step explanation:

The external angles of a polygon sum to 360 degrees.

So it's 360/18 = 20.

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Find the vertex and the x-inter of the function given below. y = x^2 + 2x + 6

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Answer: Vertex = (-1, 5) x-intercepts = No real solutions

Step-by-step explanation:

Vertex = -2/2= -1

-1^2 + 2(-1) +6

1 -2 +6

-1 +6

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4 -4(1)(6)

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Where are the numbers

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Determine which values of p the following integrals converge. Give your answer in each case by selecting the appropriate inequal

sashaice [31]

Answer:

Step-by-step explanation:

$\int\limits^2_1 {\frac{1}{x(lnx)^p} } \, dx$

this can be done by substitute lnx = u

dx/x = du

When x =1, u =0 and when x =2, u = ln 2

So integral = $\int\limits^{ln2} _0 {du/u^p} \\\=\frac{u^{-p+1} }{-p+1}$

We find that this integral value is not definid for p =1

Hence for values of p other than 1, this converges.

When we substitute limits

$\frac{1}{1-p} ((ln2)^{1-p} -1)$

and converges for p ≠1

b) $\int\limits^1_0 {lnx}/x^p \, dx \\\int \frac{\ln \left(x\right)}{x^p}dx=\frac{1}{-p+1}x^{-p+1}\ln \left(x\right)-\frac{x^{-p+1}}{\left(-p+1\right)^2}+C$

So not converging for p =1

But ln x is defined only for x >0

So integral 0 to 1 makes this integral not valid and hence not convergent.

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