Answer:
Step-by-step explanation:
160lb.
The mean of the weights of a group of 100 men and women is 160lb. If the number of men in the group is 60 and the mean weight of the men is 180lb, what is the mean weight of the women? For a set of data, the lower quartile is 19, the median is 31, and the upper quartile is 48.
y=13x+5 ===(0,5) , (-2, -21)
y=-3x ===(0,0) , (-3,9)
y=x-10 ===(8,-2) , (-5, -15)
Answer: Y= -5x+2
First we need to find slope
M= y2-y1/x2-x1
M= -3-2/1-0
M= -5/1
M= -5
Now using slope intercept form we can solve this equation
Y-y1=m(x-x1)
Y-2=-5(x-0)
Y-2=-5x+0
Y= -5x+2
hope this helps!!
Please tell me if I am incorrect, I enjoy learning from my mistakes:)
You first wanna find <BAD, because if AB is perpendicular to AC, then it has to form a 90 degree angle. So 90-56=34 degrees. So now you have a 34 & 63 degrees in the ABD triangle. In a triangle, all angles add up to equal 180 degrees. So 34+63+x=180...and x=83. So <ADB= 83 degrees. Now you want to find angle ADC...which you can just subtract 83 from 180 (because <ADB & <ADC forms 180 degree angle). You will then get 97 as angle ADC. So, the same thing as before, add up 56+97+x=180, because all angles (in the triangle ADC) add up to be 180 degrees. X will then equal 27 degrees. Angle ACB= 27 degrees.
Answer: x=15
Step-by-step explanation:
To solve problems like this you need to simplify the equations on both sides and then isolate your variable x.
