What is 2,200x in scientific notation?
1 answer:
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Answer:
see below
Step-by-step explanation:
Use the distributive property:
(y^2 +3y +7)(8y^2 +y +1)
= y^2(8y^2 +y +1) +3y(8y^2 +y +1) +7(8y^2 +y +1)
= 8y^4 +y^3 +y^2 + 24y^3 +3y^2 +3y + 56y^2 +7y +7
= 8y^4 +y^3(1 +24) +y^2(1 +3 +56) +y(3 +7) +7
= 8y^4 +25y^3 +60y^2 +10y +7 . . . . . matches the last choice
Answer:
(a) 720 -2x
(b) 0 ≤ x ≤ 360
(c) A = x(720 -2x)
(d) (30.334, 68.645) ∪ (291.355, 329.666) (two disjoint intervals)
(e) x = 180 ft, the other side = 360 ft; total area 64,800 ft²
Step-by-step explanation:
(a) The two parallel sides of the fenced area are each x feet, so the remaining amount of fence available for the third side is (720 -2x) ft. Then ...
length = 720 -2x
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(b) The two parallel sides cannot be negative, and they cannot exceed half the length of the fence available, so ...
0 ≤ x ≤ 360
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(c) Area is the product of the length (720-2x) and the width (x). The desired function is ...
A = x(720 -2x)
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(d) For an area of 20,000 ft², the values of x will be ...
20000 = x(720 -2x)
2x² -720x +20000 = 0
x = (-(-720) ±√((-720)² -4(2)(20000)))/(2(2)) = (720±√358400)/4
x = 180 ±40√14 = {30.334, 329.666} . . . feet
For an area of 40,000 ft², the values of x will be ...
x = 180 ±20√31 ≈ {68.645, 291.355} . . . feet
The values of x producing areas between 20,000 and 40,000 ft² will be values of x in the intervals (30.334, 68.645) or (291.355, 329.666) feet.
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(e) The vertex of the area function is at the axis of symmetry: x = 180. The corresponding dimensions are ...
180 ft × 360 ft
and the area of that is 64,800 ft².
