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3 years ago

5

The first week of January there are 49 dogs and 28 cats in the shelter. Throughout the month the ratio of dogs to cats remains t

he same. The last week of January there are 29 cats in the shelter. How many dogs are there?

1 answer:

Katen [24]3 years ago

6 0

There should be a total of 50 dogs if there’s 29 cats because -

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Solve the following inequality: 5x+3 < 6x+2

grigory [225]

Answer:

5x + 2x + 7x

Step-by-step explanation:

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3 years ago

Convert 5 killogram into grams . here are the answer choices A.5,000 B.500 C.50 D. 5,500

serious [3.7K]

The answer to this question is 5000

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3 years ago

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HELPPP ASAPP Bernie's Bars has determined that a granola bar measuring 3 inches long has a z-score of +1 and a granola bar measu

Len [333]

Answer:

Standard deviation of the length of granola bars produced at Bernie's Bars is 0.50

Step-by-step explanation:

We are given the following information in the question:

Formula:

$z_{score} = \displaystyle\frac{x - \mu}{\sigma}$

where,

μ is the mean and σ is the standard deviation.

Putting the values we get:

$\displaystyle\frac{ 3- \mu}{\sigma} = 1\\\\3 = \sigma + \mu\\\\\displaystyle\frac{ 3.5- \mu}{\sigma} = 2\\\\3.5 = 2\sigma + \mu$

Solving the two obtained equations:

Subtracting the two obtained equation, we have:

$3.5-3 = \mu + 2\sigma - \mu -\sigma\\\sigma = 0.5$

Hence, standard deviation of the length of granola bars produced at Bernie's Bars is 0.50

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3 years ago

Read 2 more answers

The equation for picture D is 13 4/5 = w + 3 4/5. What is the solution? Write the number answer only. Please do not write the va

aksik [14]

Answer:

13 4/5 = 10 + 3 4/5

Step-by-step explanation:

4 0

2 years ago

Need help please help me

ANTONII [103]

Megan:
x to the one third power = $x ^{1/3}$
<span>x to the one twelfth power = </span> $x ^{1/12}$

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span> $\frac{x ^{1/3}}{x ^{1/12}}$
<span>
Since </span> $\frac{ x^{a} }{ x^{b} } = x ^{a-b}$
then $\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}$

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

$\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}$

Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span> $\sqrt[32]{x* x^{2} * x^{5} }$
<span>
Since </span> $x^{a}* x^{b}= x^{a+b}$
Then $\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }$

Since $\sqrt[n]{x^{m}} = x^{m/n} }$
Then $\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}$

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.

3 0

3 years ago