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3 years ago

9

Max kept track of the number of each size of children's caps and each size of adult caps he had for some football teams in his s

tore. Which graph would be the most appropriate to display this information? A. double-bar graph B. line graph C. circle graph D. line plot

2 answers:

Korolek [52]3 years ago

5 0

A. a double bar graph

aliya0001 [1]3 years ago

3 0

Your answer is....

D) Line Plot.

≈≈≈≈ Glad I Could Help, And Good Luck! ≈≈≈≈

My Name: AnonymousGiantsFan

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Martha is training for a duathlon, which includes biking and running. She knows that yesterday she covered a total distance of o

umka21 [38]

<u>Answer:</u>

<u>Distance:</u> 6x + 15.5y > 55.5

<u>Time:</u> x + y > 4.5

<u>Step-by-step explanation:</u>

We are given that Martha is training for a duathlon and she covered a total distance of over 55.5 miles in more than than 4.5 hours of training.

Also, she runs at a speed of 6 mph and bikes at a rate of 15.5 mph.

We are to write inequalities representing the distance she traveled and the total time she spent training.

<u>Distance:</u> 6x + 15.5y > 55.5

(formula for distance = speed x time so speeds for running and biking are multiplied by their number of hours)

<u>Time:</u> x + y > 4.5

(she trained for more than 4.5 hours, x hours for running and y hours for biking.

4 0

3 years ago

The endpoints of EF¯¯¯¯¯¯¯¯ are E(−4,12) and F(3,15). Find the coordinates of the midpoint M..

Ray Of Light [21]

Answer:

(-1/2, 27/2)

Step-by-step explanation:

Midpoint formula: (x^1 +x^2/ 2, y^1 +y^2/ 2)

(-4 +3 /2, 12+15/ 2) -> (-1/2, 27/2)

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3 years ago

What type of arc is AB

stiv31 [10]

I'm sorry I don't know the answer but I do have to say that you are loved and no matter how many mistakes you make you will still always be loved. Step-by-step explanation:

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3 years ago

Read 2 more answers

Use triangle ABC drawn below & only the sides labeled. Find the side of length AB in terms of side a, side b & angle C o

Brrunno [24]

Answer:

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

Step-by-step explanation:

Given:

The above triangle

Required

Solve for AB in terms of a, b and angle C

Considering right angled triangle BOC where O is the point between b-x and x

From BOC, we have that:

$Sin\ C = \frac{h}{a}$

Make h the subject:

$h = aSin\ C$

Also, in BOC (Using Pythagoras)

$a^2 = h^2 + x^2$

Make $x^2$ the subject

$x^2 = a^2 - h^2$

Substitute $aSin\ C$ for h

$x^2 = a^2 - h^2$ becomes

$x^2 = a^2 - (aSin\ C)^2$

$x^2 = a^2 - a^2Sin^2\ C$

Factorize

$x^2 = a^2 (1 - Sin^2\ C)$

In trigonometry:

$Cos^2C = 1-Sin^2C$

So, we have that:

$x^2 = a^2 Cos^2\ C$

Take square roots of both sides

$x= aCos\ C$

In triangle BOA, applying Pythagoras theorem, we have that:

$AB^2 = h^2 + (b-x)^2$

Open bracket

$AB^2 = h^2 + b^2-2bx+x^2$

Substitute $x= aCos\ C$ and $h = aSin\ C$ in $AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = h^2 + b^2-2bx+x^2$

$AB^2 = (aSin\ C)^2 + b^2-2b(aCos\ C)+(aCos\ C)^2$

Open Bracket

$AB^2 = a^2Sin^2\ C + b^2-2abCos\ C+a^2Cos^2\ C$

Reorder

$AB^2 = a^2Sin^2\ C +a^2Cos^2\ C + b^2-2abCos\ C$

Factorize:

$AB^2 = a^2(Sin^2\ C +Cos^2\ C) + b^2-2abCos\ C$

In trigonometry:

$Sin^2C + Cos^2 = 1$

So, we have that:

$AB^2 = a^2 * 1 + b^2-2abCos\ C$

$AB^2 = a^2 + b^2-2abCos\ C$

Take square roots of both sides

$AB = \sqrt{a^2 + b^2-2abCos\ C}$

6 0

3 years ago

Question five for geometry quiz

Helga [31]

The two tangents are parallel to each other because the two lines perpendicular to the same line are parallel to each other.

Lk + JK = JL

The answer is Parallel to each other

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3 years ago