TABLE / BOX
| h ||||||| 0 | 1 | 2 | 3 | 5 | 9 | 12 | 13 | 15
| M(h) | 0| .1/.5 |.2/.5|.3/.5| 1 |1.8|2.4| 2.6| 3
I tried my best on putting it in order sorry if its not clear
make shure to put brainliest!
Given that Jaquelyn was tardy on Monday, there is a 12 percent chance she will be late on Tuesday as well.
What is the Probability?
How likely it is that a stated event would occur is assessed using probability. The event would have a probability of 1 if it happened with certainty. The probability of an occurrence would be zero if it were absolutely guaranteed that it would not occur.
As getting late on Monday and Tuesday are independent events, their probabilities can be multiplied.
So the probability of getting late on Tuesday, given she was late to school on Monday = Probability of being late on Monday x Probability of she being late on Monday and she is late on Tuesday 60% of the time.
= 0.2 x 0.6
= 0.12
Thus the approximate probability that Jaquelyn will be late on Tuesday, given she was late to school on Monday will be 0.12
Learn more about Probability here :
brainly.com/question/11234923
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3/4 of milk: because the bigger the number the smaller the size
The answer to a "sum and difference" problem is that the larger number is the average of those given: (43 +15)/2 = 29.
The smaller number can be computed any of several ways, but subtracting the difference works: 29 -15 = 14
The larger number is 29.
The smaller number is 14.
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You can let the numbers be a and b, and let the sum and difference be s and d. Then you have
.. a + b = s
.. a - b = d
Add these two equations, and you find "b" is eliminated:
.. 2a = s + d
.. a = (s + d)/2 . . . . . . the average of the sum and difference
.. b = a - d . . . . . . . . . from the second equation
This solution is generic. Even if you have to "show work" on such a problem, you can use this known result to check your work.
