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Dominik [7]
3 years ago
13

Help me solve these with work thanks!

Mathematics
2 answers:
mars1129 [50]3 years ago
6 0

Answer:

1. 3x-5=22

+5

3x=27

divide both sides by 3

x=9

2. 2k-6+3k=9

5k (combine like terms) +6

5k=15

divde by 5

k=3

3. 2(4x-3)=9x+4

distribute= 8x-6=9x+4

-9x & +6

-x=10

divide by -1 (that's what x is essentially in that form)

x=-10

4. -84=7p

divide by 7

p=-12

EastWind [94]3 years ago
3 0

Hello Blake,

Here is the answers and solutions for your set of problems.

1. 3x - 5 = 22

    i. Add 5 to 22 = 27

    ii. Divide 27 by 3 = 9

Answer = 9

2. 2k - 6 + 3k = 9

    i. Add +2k and +3k (5k - 6 = 9)

    ii. Add 9 and 6 = 15

    iii. Divide 15 by 3 = 5

Answer = 5

<h2>Will do next 2 soon</h2>

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Answer:

Step-by-step explanation:

A right angle triangle is formed.

The length of the guy wire represents the hypotenuse of the right angle triangle.

The height of the antenna represents the opposite side of the right angle triangle.

The distance, h from base of the antenna to the point on the ground to which the antenna is attached represents the adjacent side of the triangle.

To determine h, we would apply Pythagoras theorem which is expressed as

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41² = 32.8² + h²

1681 = 1075.84 + h²

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To determine the angle θ that the wire makes with the ground, we would apply the the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos θ = 24.6/41 = 0.6

θ = Cos^-1(0.6)

θ = 53.1°

7 0
4 years ago
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\large -6x+6y=6<br> \large 6x+3y=12
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Answer:

the solution of the system is:

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I suppose that we want to solve the equation:

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Let's isolate y in the first equation:

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y = (6 + 6*x)/6

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8 0
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