Please help with my math I'm begging you

In each figure below, find m<1 and m<2 if a is parallel to b. You don't have to show work.

Gekata [30.6K]

Answer:

m <5 = 71 degrees.

m <8 = 109 degrees.

5 0

3 years ago

john ran at a pace of 3.5 miles per hour for a distance of 10.5 miles. how many minutes did it take him to run 10.5 miles? use t

Rainbow [258]

The minutes it takes him to run 10.5 miles is 180 minutes

<h3>How many minutes did it take him to run 10.5 miles?</h3>

The given parameters are

Speed = 3.5 miles per hour

Distance = 10.5 miles

The time is calculated as:

Time = Distance/Speed

So, we have

Time = 10.5 miles/3.5 miles per hour

Evaluate the quotient

Time = 3 hours

Convert to minutes

Time = 180 minutes

Hence, the minutes it takes him to run 10.5 miles is 180 minutes

Read more about speed at:

brainly.com/question/6504879

#SPJ1

5 0

1 year ago

Zelma buys p pounds of bananas for $0.40 per pound she pays the clerk with a $20 bill the clerk subtract the total cost of the b

Sloan [31]

You didnt include the (presumably) multiple choice answers. My guess is that the answer would be along the lines of: 20 - (P times .40)

7 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$