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olga2289 [7]
3 years ago
14

(-6x^3+2x^2-2x)/(2x-1) how do I solve using long division?

Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0
Check  the picture below.

the idea being, to cancel out the leftmost term in the dividend, you multiply the leftmost term in the divisor, by something that will "mimic" or equate the leftmost term in the dividend, and then you slap the negative -( ) to the expression, and poof it goes.

nignag [31]3 years ago
4 0
(-6x^3+2x^2-2x):(2x-1)=-3x^2-\dfrac{1}{2}x-1\dfrac{1}{4}\ R=-1\dfrac{1}{4}\\\\-6x^3+2x^2-2x=\left(-3x^2-\dfrac{1}{2}x-1\dfrac{1}{4}\right)(2x-1)-1\dfrac{1}{4}

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Alex787 [66]

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The inequalities that represent the maximum weights are:

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<em />

Let the maximum weight be represented with x

In inequality, maximum means less than or equal to i.e. \le

<u>(a) 2 axles</u>

The maximum weight, here is 40000.

So, the inequality is:

x \le 40000

<u>(b) 3 axles</u>

The maximum weight, here is 60000.

So, the inequality is:

x \le 60000

<u>(c) 4 axles</u>

The maximum weight, here is 80000.

So, the inequality is:

x \le 80000

<em>See attachment for the graphs of each inequality</em>

Read more about inequalities at:

brainly.com/question/11612965

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As ,x =0 then y= 49 and x_{1} =1 then y_{1}  = 7,

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So, Option (1),(4) and (5) are correct.

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