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Alex Ar [27]
2 years ago
5

Camille's kitchen has an area of 80 square feet. The kitchen is 8 times as many square feet as Camille's pantry. If the pantry i

s 2 feet wide, what is the length of the pantry? First find the area of the pantry. Solve on paper and check you answer on Zearn. The area of the pantry is square ft.
Mathematics
1 answer:
Inessa05 [86]2 years ago
5 0

Answer:

Length of the pantry = 5 feet

Step-by-step explanation:

Camille's kitchen has an area of 80 square feet. The kitchen is 8 times as many square feet as Camille's pantry.

Step 1

Area of Camille's kitchen = 8(Area of Camille's pantry)

Area of Camilla kitchen = 80 square feet

80 square feet = 8(Area of Camille's pantry)

Area of Camille's pantry = 80 square feet/8

Therefore:

Area of Camille's pantry = 10 square feet

Step 2

If the pantry is 2 feet wide, what is the length of the pantry?

The shape of the pantry is rectangular hence:

The area of the pantry = Length × Width

Area of the pantry = 10 square feet

Width = 2 feet

Length = Area of the pantry/Width

Length = 10 square feet/2 feet

Length = 5 feet

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From 1960 to 1980 , the consumer price index (cpi) increased from 29.6 to 82.4. If a frozen chicken pie cost $0.28 in 1960 and t
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CPI in 1960 = 29.6

CPI in 1980 = 82.4

Growth (%) in CPI = \frac{\text{CPI in 1980 - CPI in 1960}}{\text{CPI in 1960}} × 100

⇒ Growth (%) in CPI = \frac{82.4-29.6}{29.6} × 100

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⇒ Growth (%) in CPI = 178.4%

Now, we know that price of frozen chicken pie in 1960 = $0.28

Also, we know that over 1960 to 1980, frozen chicken pie price grew at the same rate as CPI

Hence, Price of Chicken Pie in 1980 = Price of Chicken Pie in 1960 × (1 + Growth in CPI)

⇒ Price of Chicken Pie in 1980 = 0.28 × (1 + 178.4%)

⇒ Price of Chicken Pie in 1980 = 0.28 + (0.28 × 178.4%)

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Hence, price of chicken pie in 1980 would be ~$0.78

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If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
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Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

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(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

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