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Anton [14]
3 years ago
14

The propeller blades on a submarine have a radius of 6 feet. At full speed, they turn at 120 revolutions per minute. What is the

angular velocity, in radians per minute, at the tip of the blade?
Mathematics
2 answers:
Kamila [148]3 years ago
5 0

One revolution also corresponds to an angular displacement of 2π rad.

So, the angular velocity is

120 rev/min = (120 rev/min) * (2π rad/rev) = 240π rad/min

Gelneren [198K]3 years ago
5 0

Answer:

753.98 rad/min

Step-by-step explanation:

on edge, it asks for you to round to the nearest hundredth, causing me to assume that you need to multiply 240(pi)

the whole answer is 753.9822369, but it asks for you to round.

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Alexus [3.1K]

Answer:\frac{-7\sqrt{2} }{4}

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get \sqrt{16}-x\sqrt{8} =11. We know that the square root of 16 is ±4, so now our equation is ±4 - x\sqrt{8}=11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - x\sqrt{8}=11. We can use inverse operations to make the a little easier to solve: -7= x\sqrt{8}. We divide both sides by \sqrt{8} to get \frac{-7}{\sqrt{8} } =x, which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by \frac{\sqrt{8} }{\sqrt{8} } (which is equal to one so we can use it) which is equal to \frac{-7\sqrt{8} }{8}. Let's finish this by simplifying it. \sqrt{8} =2\sqrt{2} (2x2^{2}). We can simplify it further by simplifying the 2, making it \frac{-7\sqrt{2} }{4}.

Hope this wasn't too confusing! I'll answer any questions.

8 0
3 years ago
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-(1 - 9x) - 8 helpppp meeeeeee
madreJ [45]

Answer

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Step-by-step explanation

sorry im late

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svetlana [45]

Answer:

7/5

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

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(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

Please, please give brainliest, it would be greatly appreciated, I only need one more before I advance, thanks!

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