Which of these is the area of a sector of a circle with r = 18”, given that its arc length is 6π? A) 54.00 in2 ... Best Answer: Perimeter P is 2piR where R=18" Hence ... Area of total circle is piR^2=324pi sq inches so Area/6 or 54pi sqin which ='s the combined areas of the 18"equilateral triangle plus the sector.Answer:
i hop this help you out
Step-by-step explanation:
Well if I was to follow the pattern then after four years it would be 240
Domain: (-∞,∞)
Range: (3,∞)
x-intercepts: none
y-intercepts: (0,7)
Interval positive: (3,∞)
Interval negative: none
Interval increasing: (7,∞)
Interval decreasing: (-∞,7)
I'm not sure what the average rate of change over is though.
Answer:
17) x = 58.1 units
18) x = 17 units
Step-by-step explanation:
The concept of similar triangles will be applied.
It is evident that the AAA congruence property is responsible for the similarity of the two triangles in the 2 cases. The theorem is
- Triangles are similar if the measure of all three interior angles in one triangle are the same as the corresponding angles in the other.
So, the corresponding sides from the two triangles can be written as a ratio of one another
17)
The most obvious tell here is the largest angle in the two triangles, the sides directly opposite this angle in the two triangles can be written in a ratio such that
(95.2/13.6) = 7
indicating that the bigger triangle is exactly 7 times the smaller one.
So,
(95.2/13.6) = (53.2/7.6) = (x/8.3) = 7
x = 7 × 8.3 = 58.1
18)
The obvious tell here is the smallest common angle for the two triangles, the two other corresponding sides can then be written in a ratio, matching the bigger side in the two triangles to each other.
(39.5/7.9) = (37.5/7.5) = (x/3.4)
(x/3.4) = 5 (Indicating thay the bigger triangle is 5 times bigger than the smaller one.
x = 3.4 × 5 = 17 units.
Hope this Helps!!!
If in a fraction, the numerator or the denominator or both are fractions, then it is called a complex fraction.
Example 1:
Here, since the numerator is a fraction, it is a complex fraction.
Example 2:
Here, since the numerator and the denominator are fractions, it is a complex fraction.
