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expeople1 [14]
3 years ago
10

Is -1/125 a terminating or repeating decimal is -7/60 a terminating or repeating decimal

Mathematics
2 answers:
laiz [17]3 years ago
6 0

Answer:

-1/125 is a terminating decimal. -7/60 is a repeating decimal.

Step-by-step explanation:

When you convert -1/125 into a decimal, you get − 0.008.

                                                                                        _

When you convert -7/60 into a decimal, you get − 0.11  6.

harina [27]3 years ago
6 0

Answer:

-1/125 is a terminating decimal, -7/60 is a repeating decimal.

Step-by-step explanation:

-1 divide by 125 equals exactly -0.008 and stop there.

-7 divide by 60 equals -0.116 six repeating.

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Answer:

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Step-by-step explanation:

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Fill in the y values of the t–table for the function y = RootIndex 3 StartRoot x EndRoot
bulgar [2K]

Answer:

x            y

-8          -2

-1          -1

0          0

1           1

8          2

Step-by-step explanation:

The given function is  

y=\sqrt[3]{x}

We need to find the y-values for the given t-table.

In the given table the x-values are -8, -1, 0, 1, 8.

At x=-8,

y=\sqrt[3]{-8}=-\sqrt[3]{2^3}=-2

At x=-1,

y=\sqrt[3]{-1}=-\sqrt[3]{1^3}=-1

At x=0,

y=\sqrt[3]{0}=0

At x=1,

y=\sqrt[3]{1}=\sqrt[3]{1^3}=1

At x=-8,

y=\sqrt[3]{8}=\sqrt[3]{2^3}=2

Therefore, the required table is:

x            y

-8          -2

-1         -1

0          0

1           1

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8 0
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kykrilka [37]
Exact form is 469/12 decimal form is 39.083 repeating and mixed number form is 39/1/12
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vichka [17]

Answer:

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Step-by-step explanation:

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4 years ago
In regional spelling bee, the 8 finalists consist of 3 boys and 5 girls. Find the number of sample point the sample space S for
Minchanka [31]

Answer:

i) There are 40320 possible orders

ii) There are 336 possible orders for the first 3 positions.

Step-by-step explanation:

Given: The number of finalists = 8

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To find the number of sample point the sample space S for the number of possible orders, we need to find factorial of 8!

The number of possible orders = 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) From all 8 finalist, we need to choose first 3 position. Here the order is important. So we use permutation.

nPr =\frac{n!}{(n - r)!}

Here n = 8 and r = 3

Plug in n =8 and r = 3 in the above formula, we get

8P3 = \frac{8!}{(8 - 3)!}

= \frac{8!}{5!} \\= \frac{1.2.3.4.5.6.7.8}{1.2.3.4.5}

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= 336

So there are 336 possible orders for the first 3 positions.

3 0
3 years ago
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