Since 
are linearly dependent, there exist coefficients 
such that
Now, a linear combination of the new vectors would look like this:
Which simplifies to
So, any linear combination of 
is also a linear combination of . This implies that we can choose the coefficients for a linear combination that will give the zero vector.
In particular, if are the coefficients such that
we can choose
And we have
Answer:
repeating decimal/number
Step-by-step explanation:
If you divide 11 by 24, you get 0.458333333...
The 3 gets repeated, so 11/24 is a repeating decimal/number
Answer:
1) 1 | 3, 5, 8
2| 2, 4, 6, 6
3| 4, 8, 9
4| 5, 5
5| 1, 5, 6
Step-by-step explanation:
You put the tens place in the "stem" section and the ones in the "leaf" section. For 3 digit number you but both the hundreds and tens in the stem spot. Ex) 23 | 1, 5, 8, 9
Answer:
approximately 8.16 times
Step-by-step explanation:
Answer:
A natural number is a number that occurs commonly and obviously in nature. As such, it is a whole, non-negative number.
Step-by-step explanation:
