For this case the area of the sector is given by:
A = (S '/ S) * (pi) * (r ^ 2)
Where,
S '/ S = relation of arcs
r: radius of the circle
Substituting values we have:
A = (7.4/360) * (3.14) * (13 ^ 2)
A = 10.9080111
Rounding off we have:
A = 10.9 cm^2
Answer:
the area of sector is:
A = 10.9 cm^2
Answer:
a. The mean growth of plant is same for each type of soil.
Step-by-step explanation:
The analysis of variance is statistical procedure used to assess the equality of more than two means by computing two different estimate of variances. Basically when we have more than two means to compare, we can't use t-test or z-test because these procedure will be tedious and time taking. So, the null hypothesis will be the same. Hence the null hypothesis in the given scenario is that "the mean growth of plant is same for each type of soil".
Answer:
option a is the answer
Step-by-step explanation:
put the value of x in each expression as x = -2
you'll see that in option a the expression becomes

which is not defined. hence -2 is excluded value
Answer: B
Step-by-step explanation:
First, simplify the main expression. The answer is 21.
Then simplify A. It is -106. That is not equal to 21 so A is wrong.
Then simplify B. That is 21. That means B is correct and you don’t have to solve C or D.
Answer:
A. ![\left[\begin{array}{cc}0.93&0.07&\\0.01&0.99&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0.93%260.07%26%5C%5C0.01%260.99%26%5Cend%7Barray%7D%5Cright%5D)
B. (0.85 0.15)
C. 79.2% population in the city while 20.8% population in the suburb
Step-by-step explanation:
(a) The transition matrix for the information is
C S
(b) the probability vector for the information is

and this gives us
(0.85 0.15)
(c) we simply multiply the above two matrices to find the percent of the population can be expected to be in each category after one year after
in the city there are 79.2% while in the suburb, there are 20.8%