3 years ago

Identify the vertex and zeros of the function.

Mathematics

1 answer:

kirza4 [7]3 years ago

5 0

Answer:

zeros: x=-6, x=2

Vertex: (-2,-16)

Step-by-step explanation:

try using math-way

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miv72 [106K]

You need to use division.

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3 years ago

What are the roots of the quadratic equation 2x2+7x+4=0? Select all that apply.

skad [1K]

Answer:

option A and B

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

Step-by-step explanation:

we have

$2x^2+7x+4=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$2x^2+7x+4=0$

$a=2\\b=7\\c=4$

substitute in the formula

$x=\frac{-7\pm\sqrt{7^{2}-4(2)(4)}} {2(2)}$

$x=\frac{-7\pm\sqrt{17}} {4}$

$x=\frac{-7+\sqrt{17}} {4}$

and

$x=\frac{-7-\sqrt{17}} {4}$

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3 years ago

Class 6 MATHS is this correct?

Rashid [163]

Answer:

yes ur right

Step-by-step explanation:

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2 years ago

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The system shown has the unique solution (2, y, z). Solve the system and select the values that complete the solution. y = 0 y =

madreJ [45]

So we are given a system:
$3x-2y+3z=0\\
-3x - 5y - 5z= -21$
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Multiply the first equation by -5 and the second by 2 we get the system:
$10y-15z=30\\
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Adding the two equations we get :
$-25z=0\text{ then}z=0.$
We find the value of y by using any of the other equations like this:
$-2y=-6\\y=3.$
Final solution:
$z=0,y=3$

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3 years ago

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0.03*42 this gives you a 3% discount

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3 years ago