The power of products property states that for number
enclosed in a bracket or parenthesis, if it is raised to a power, it must be
multiplied to the power of the enclosed number no matter how different the base
is. You cannot add it because it is not raised. You can only add it if they
have the same base. But in this problem, you will just multiply it. The breakdown
of the solution to this problem is shown below. So,
<span><span>• (2x⁵y²)³=(21x3x5*3y2*3)
= 6x15y6</span><span>
</span></span>
Hello!
1 quart=4 cups
4(4)=16
1/4(4)=4/4
16+4/4=16 4/4
Our final answer is 16 4/4 cups.
I hope this helps!
Answer:
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Step-by-step explanation:
we know that
The circumference of a circle is equal to

we have

Convert to an improper fraction
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substitute


Answer: No, Titus is incorrect.
Step-by-step explanation: Two shapes are <u>congruent</u> when they have the same size and shape, but one is created of rotation, reversion or translation of the other.
So, hexagons FEDCBA and F'E'D'C'B'A' are congruent because they have the same size and shape, however they are reversed and translated from each other, i.e.:
Comparing the coordinates of both hexagons:
F (-6,6) → F' (6, -4)
A (-10,6) → A' (10,-4)
E (-4,4) → E' (4, -6)
B (-12,4) → B' (12, -6)
D (-6,2) → D' (6, -8)
C (-10,2) → C' (10, -8)
We notice that the transformation necessary to transform FEDCBA into F'E'D'C'B'A' is
- multiply x-coordinate by (-1);
- subtract y-coordinate by 10;
Therefore, it is (x,y) → ( -x, y-10).
So, Titus is incorrect about the transformations that prove the hexagons are congruent.