an = a1r^(n-1)
a5 = a1 r^(5-1)
-6 =a1 r^4
a2 = a1 r^(2-1)
-48 = a1 r
divide
-6 =a1 r^4
---------------- yields 1/8 = r^3 take the cube root or each side
-48 = a1 r 1/2 = r
an = a1r^(n-1)
an = a1 (1/2)^ (n-1)
-48 = a1 (1/2) ^1
divide by 1/2
-96 = a1
an = -96 (1/2)^ (n-1)
the sum
Sn = a1[(r^n - 1/(r - 1)]
S18 = -96 [( (1/2) ^17 -1/ (1/2 -1)]
=-96 [ (1/2) ^ 17 -1 /-1/2]
= 192 * [-131071/131072]
approximately -192
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Answer:
Length of ribbon = 40.86 inches
Step-by-step explanation:
Length of the ribbon = circumference of the dish = πD
D = diameter = 13 inches
Length of ribbon = 22/7 x 13 = 40.857143 inches
Answer:
(a) P=0.850 (b) P=0.460 (c) P=0.053 (d) P=0.457 (e) P=0.543
Step-by-step explanation:
(a) Compute the probability that a randomly selected peanut M&M is not green.
(b) Compute the probability that a randomly selected peanut M&M is blue or orange.
(c) Compute the probability that two randomly selected peanut M&M’s are both orange.
(d) If you randomly select three peanut M&M’s, compute that probability that none of them are orange.
(e) If you randomly select three peanut M&M’s, compute that probability that at least one of them is orange.
We have to compute the probability that only one peanut is orange, plus the probaibility that only two peanuts are orange plus the probability that the three peanuts are orange
Answer:
LCM (7, 18 and 21) = 126
Step-by-step explanation:
Step 1: Address input parameters & values
Intergers: 7 18 21
LCM (7, 18, 21) = ?
Step 2: Arrange the group of numbers in the horizontal form with space or comma separated format
7, 18 and 21
Step 3: Choose the divisor which divides each or most of the integers of in the group (7, 18 and 21), divide each integers separately and write down the quotient in the next line right under the respective integers. Bring down the integer to the next line if the integer is not divisible by the divisor. Repeat the same process until all the integers are brought to 1.
Step 4: Multiply the divisors to find the LCM 7, 18 and 21
7 × 3 × 6 = 21
LCM(7, 18, 21) = 126
The least common multiple for three numbers 7, 18, and 21 is 126