Answer:
290
Step-by-step explanation:
If the first term is 2 and the common difference is 32, then the formula for a(n) is:
a(n) = 2 + 32(n-1).
Thus, the 10th term is a(10) = 2 + 32(10-1) = 2 + 32(9) = 290
The product would be 76 if you are looking for the answer of 4•19
Answer:
45 km/h
Step-by-step explanation:
In the first part of the trip, he already covered 30 km so we can subtract that from the total distance
45 - 30 = 15
This means he has 15 km to go
He also took an hour, or 60 minutes, to get to school. We subtract the time spent of the first part and time spent talking to a friend from the 60 minutes
60 - 35 = 25
25 - 5 = 20
He took 20 minutes to cover the second part of the journey
Speed = distance/time
15/20 = 0.75
He covered 0.75 km per MINUTE
to find it in km/h, we just multiply the number by 60
0.75 x 60 = 45
Sum means add
sum of the 3 is
n+n+1+n+2
it add to 57
n+n+1+n+2=57
3n+3=57
minus 3 both sides
3n=54
divide both sides by 3
n=15
n+1=16
n+2=17
the integers are 15,16, and 17
Answer:
In First method : counting up, counting back on a number line,
If we want the quotient after dividing the number by 5 then we count how many 5 we get from 0 to the dividend.
For example : 
Since, from 0 to 30 there are six 5's obtained. ( because 5 × 6 = 30 )
Thus, 
In Second Method : dividing by 10, and then doubling the quotient.
First we divide the number by 10 then multiply the quotient by 2.
For Example: 
Since, 

Thus, 
Now, when we compare the above methods then we conclude that for the smaller numbers first method is appropriate because for small numbers we can easily count total 5's from 0. While for large numbers Second method is appropriate because it is hard to count the total 5's for the large number.