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alina1380 [7]
3 years ago
6

The volume of a cube is given by , where s is the side length of the cube. What is the difference of the volumes of two cubes wi

th side lengths of 5 meters and 4 meters?
Mathematics
2 answers:
zysi [14]3 years ago
5 0

Answer:

61 cubic meters

Step-by-step explanation:

1) Find the volume of the cube where s=4

1a) V= s*s*s

1b) Insert in side length

V=4*4*4

1c) solve

V=64 cubic meters

2) Find volume of 2nd cube by repeating same steps where s=5

2a) V=125 cubic meters

3) Subtract to find difference

3a) 125-64

3b) Solve: 61 cubic meters

bija089 [108]3 years ago
4 0

Answer:

The cube with meters length of 5 s a bigger mass if the width of both cubes are the same

Step-by-step explanation:

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8.25(12)+3.99(8)

99+31.92

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Dado dos ángulos complementarios, uno mide (2x + 10) y el otro (x + 20),
rusak2 [61]

Answer:

El valor de <em>x</em> es igual a 20 o <em>x</em> = 20.

Step-by-step explanation:

Lo primero que se debe saber es que <em>dos ángulos complementarios suman un ángulo recto o 90º</em>.

Supongamos que el valor de un ángulo \\ \alpha y un ángulo \\ \beta valen:

\\ \alpha = 2x + 10 [1]

\\ \beta = x + 20 [2]

Como la suma de  \\ \alpha + \beta = 90 [3]

Entonces

\\ \alpha + \beta = (2x + 10) + (x + 20) = 90

Sumamos los factores comunes entre si:

\\ (2x + x) + (10 + 20) = 90

Para la primera expresión debemos recordar que se suman sólo los coeficientes. Así:

\\ (2 + 1)x + (10 + 20) = 90

\\ 3x + 30 = 90

Para despejar la incógnita <em>x</em>, debemos tener en cuenta que <em>una igualdad no se altera si se suma, se resta, se multiplica o divide un mismo valor a cada lado de ella</em>. Por esta razón, para despejar 3x, lo primero que podemos hacer es sumar -30 a cada lado de la expresión (lo que es igual a restar 30 a cada lado de la misma). Así tenemos:

\\ 3x + 30 - 30 = 90 - 30

\\ 3x + 0 = 90 - 30

\\ 3x = 60

Ahora dividimos cada miembro de la igualdad entre 3 (o multiplicamos cada lado de la igualdad por \\ \frac{1}{3} ):

\\ \frac{3}{3}x = \frac{60}{3}

Como sabemos que:

\\ \frac{3}{3} = 1

Entonces:

\\ 1*x = \frac{60}{3}

\\ x = \frac{60}{3}

\\ x = 20

De esta manera, el valor de <em>x</em> es igual a 20 o x = 20.

Lo anterior lo podemos comprobar considerando las ecuaciones [1], [2] y [3]. Así tenemos que:

\\ \alpha = 2x + 10 [1]

Sustituimos x por el valor de 20:

\\ \alpha = 2*20 + 10 = 40 + 10 = 50

\\ \beta = x + 20 [2]

Hacemos lo mismo para [2]:

\\ \beta = 20 + 20

\\ \beta = 40

De esta manera:

\\ \alpha + \beta = 90 [3]

\\ 50 + 40 = 90

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