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s344n2d4d5 [400]
2 years ago
9

What percent of each diagram is shaded below?

Mathematics
2 answers:
STatiana [176]2 years ago
7 0

Answer:

a. 3/10

b. 1/5

c. 1/4

Step-by-step explanation:

a. 30/100 = 3/10

b. 20/100 = 1/5

c. 25/100 = 1/4

juin [17]2 years ago
5 0

Answer:

Step-by-step explanation:

You are working with 1 large square made up of 100 little squares. The little squares make up 10 columns of 10 little squares each.

A

Shaded part = 30 squares.

Entire large square = 100 small squares

% = 30 / 100 * 100 = 30%

B

Shaded part = 20 horizontal squares.

Entire large square = 100 small squares

% = 20 / 100 * 100 = 20%

C

Shaded part = 5 by 5 little squares = 25 little squares

Entire large square = 100 small squares

% = 25 / 100 * 100 = 25%

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How many solutions does -46+23=46x+23
Slav-nsk [51]

Answer:

x = -1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−46+23=46x+23

(−46+23)=46x+23(Combine Like Terms)

−23=46x+23

−23=46x+23

Step 2: Flip the equation.

46x+23=−23

Step 3: Subtract 23 from both sides.

46x+23−23=−23−23

46x=−46

Step 4: Divide both sides by 46.

46x/46 = -46/46

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What can a doctor use to determine a patient's body fat percentage?
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An artist agrees to paint a landscape painting at $0.30 per square inch. Formulas Show calculator Select the best answer If the
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First, you gotta multiply 13 by 17, which is 221, then multiply THAT by .3, which is 66.3. So the artist should charge $66.30
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3 years ago
Write 2x-10=6 in a math problem
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A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5
Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3)  = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

=  1/3 (3*(H/L)²*Q) / h²  = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q  = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

8 0
3 years ago
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