Answer:
26.39
Step-by-step explanation:
If you write .6 and .7 as fractions you get 6/10 and 7/10. If you double those you get 12/20 and 14/20, so one potential fraction between the two could be 13/20.
Answer:
Follows are the solution to this question:
Step-by-step explanation:
is invertible lines transformation
![S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \ \varepsilon\ 1 R^n\\\\](https://tex.z-dn.net/?f=S%5BT%28x%29%5D%3Dx%20%5C%20and%20%5C%20V%5BT%28x%29%5D%3Dx%20%5C%5C%5C%5Ct%27x%20%5C%20%20%5Cvarepsilon%5C%201%20R%5En%5C%5C%5C%5C)
T is invertiable linear transformation means that is
and 
Let
so,
![s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n](https://tex.z-dn.net/?f=s%5BT%28u%29%5D%3Dv%5BT%28u%29%5D%5C%5C%5C%5Cs%28v%29%3Dv%28v%29%20%5C%20%5C%20%20%5Cforall%20%5C%20%5C%20v%20%5C%20%5C%20%5Cvarepsilon%20%5C%20%5C%201%20R%5En)
Ascending order :-
10.5 , 11 , 11.5 , 14.5 , 17 , 17 , 18 , 19
Median,
={(n/2)th + (n/2 +1)th}/2
={(4)th + (5)th}/2
=(31.5)/2
=15.75
I.Q.R.,
Median of lower half,
={(n/2)th + (n/2 +1)th}/2
={(2)th + (3)th}/2
=(22.5)/2
= 11.25
Median of upper half,
={(n/2)th + (n/2 +1)th}/2
={(2)th + (3)th}/2
=35/2
=17.5
I.Q.R. = 17.5 - 11.25 = 6.25
HOPE THIS WILL HELP YOU
Answer:
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