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omeli [17]
3 years ago
9

How do you find the area of a circle with just the radius?

Mathematics
2 answers:
zloy xaker [14]3 years ago
5 0

Answer:

Oh that's easy! You find out what the radius is.. then the diameter is another one of that number. Example say that the radius is 10 then the diameter is 20 or if the radius is 7 the diameter is 14

Step-by-step explanation:

WINSTONCH [101]3 years ago
5 0

Answer:

<h2>Use the formula A = π(r²)   where r is the radius</h2>

Step-by-step explanation:

π = pi, and r is the radius.   It's the only value you need to find the area of a circle.  π is usually represented as 3.14, or you can use the π button on your calculator

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Write the vector v in the form aiplusbj​, given its magnitude left norm Bold v right norm and the angle alpha it makes with the
photoshop1234 [79]

Answer:

6\sqrt{3}i-6j

Step-by-step explanation:

Given:

The magnitude, v=12

The angle \alpha it makes with the positive​ x-axis =150^0

Now for a vector (x,y)

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Therefore:

150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}

y=-\frac{x \sqrt{3}}{3}

Similarly:

v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2

144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}

Recall that:

y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3}  \sqrt{3}}{3}=-6

Therefore: (x,y)=(6\sqrt{3}, -6)

The vector in the form ai+bj is therefore:

6\sqrt{3}i-6j

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3 years ago
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Answer:

Step-by-step explanation:

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djverab [1.8K]

Answer:

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Step-by-step explanation:

6*10^8\ and \ 3*10^6

To compare both values we divide the exponents

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for simplify exponents we use exponential property

a^m / a^n = a^(m-n)

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\frac{6*10^8}{3*10^6}=2*10^2= 200

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